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Studentka2010 [4]
3 years ago
9

PLS HELP ME ON THIS QUESTION I WILL MARK YOU AS BRAINLIEST IF YOU KNOW THE ANSWER PLS GIVE ME A STEP BY STEP EXPLANATION!!

Mathematics
1 answer:
gavmur [86]3 years ago
3 0

Answer:

D. 1:5

Step-by-step explanation:

3 students went to the zoo

15 students went to the aquarium, which is no the zoo

students who went to the zoo : students who did not go to the zoo =

= 3:15

Now we simplify the ratio by dividing both numbers by 3.

= 1:5

Answer: D. 1:5

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Someone please help out
exis [7]

Answer:

39+0.15m \leqslant 50

Step-by-step explanation:

From the question, Diana wants her total bill to be less than $50.

Diana pays a fixed monthly bill of

$39 for her mobile phone and an additional

$0.15 per minute for phone internet service.

The bill Diana pays for m minutes of using the internet is $0.15m in a month.

The total monthly bill becomes,

39+0.15m

The maximum bill she wants to pay is $50.

\implies39+0.15m \leqslant 50

This inequality can be solved to determine the number of available minutes.

4 0
3 years ago
Find the equation of line
Elza [17]

Answer:

y= -1/3x+5

Step-by-step explanation:

-1/3 is the slope (rise/run)

5 is the y-intercept

3 0
3 years ago
Find the derivative.
Aleksandr [31]

Answer:

Using either method, we obtain:  t^\frac{3}{8}

Step-by-step explanation:

a) By evaluating the integral:

 \frac{d}{dt} \int\limits^t_0 {\sqrt[8]{u^3} } \, du

The integral itself can be evaluated by writing the root and exponent of the variable u as:   \sqrt[8]{u^3} =u^{\frac{3}{8}

Then, an antiderivative of this is: \frac{8}{11} u^\frac{3+8}{8} =\frac{8}{11} u^\frac{11}{8}

which evaluated between the limits of integration gives:

\frac{8}{11} t^\frac{11}{8}-\frac{8}{11} 0^\frac{11}{8}=\frac{8}{11} t^\frac{11}{8}

and now the derivative of this expression with respect to "t" is:

\frac{d}{dt} (\frac{8}{11} t^\frac{11}{8})=\frac{8}{11}\,*\,\frac{11}{8}\,t^\frac{3}{8}=t^\frac{3}{8}

b) by differentiating the integral directly: We use Part 1 of the Fundamental Theorem of Calculus which states:

"If f is continuous on [a,b] then

g(x)=\int\limits^x_a {f(t)} \, dt

is continuous on [a,b], differentiable on (a,b) and  g'(x)=f(x)

Since this this function u^{\frac{3}{8} is continuous starting at zero, and differentiable on values larger than zero, then we can apply the theorem. That means:

\frac{d}{dt} \int\limits^t_0 {u^\frac{3}{8} } } \, du=t^\frac{3}{8}

5 0
3 years ago
If 4,5 reflected across the x-axis, the new point is located at....?
hodyreva [135]
The new point would be at 4, -5
3 0
3 years ago
Read 2 more answers
Help please for 13 coins
taurus [48]

Answer:

-146.03008

Step-by-step explanation:

(-8.149)(17.92) = -146.03008

5 0
3 years ago
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