What is the area of the regular polygon

2 answers:

7 0

To find the area of aregular polygon, you use an apothem — a segment that joins the polygon's center to the midpoint of any side and that is perpendicular to that side

dalvyx [7]3 years ago

3 0

A regular polygon is equilateral (it has equal sides) and equiangular (it has equal angles). To find the area of a regular polygon, you use an apothem — a segment that joins the polygon's center to the midpoint of any side and that is perpendicular to that side (segment HM in the following figure is an apothem).

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Whats the answer to these? (These are called Proper fractions.)

Darya [45]

Answer to the first question: 7/10ths of a mile

Explaination: When adding fractions, you need to have a common denominator. Since dividing 3/10 by 2 to get a denominator of 5 makes 3 a decimal, it's easier to multiply 2/5 by 2 to get a denominator of 10. You do the same to the top that you do to the bottom: $\frac{2*2}{5*2} = \frac{4}{10}$ . From there, just add 4/10 and 3/10 to get the answer: 7/10ths of a mile.

Answer to the second question: Daniel read three (3/10) more books

Explaination: Since you can't evenly multiply 5 or 2 to get the opposite number, it's easier to multiply to the lowest common multiple. The easiest way to find that is to multiply both denominators (5*2=10). You'll have to multiply the numerator by the same amount you multipled the denominator by. For Daniel, that would mean: $\frac{4*2}{5*2} = \frac{8}{10}$ . For Edgar, that would mean: $\frac{1*5}{2*5} = \frac{5}{10}$ . So, Daniel read 3 more books than Edgar.

Answer to the third question: 2/4 mile (or 1/2 a mile)

Explaination: 2/8 can be simplified, by dividing the top and bottom by 2, resulting in 1/4. Since both fractions have the same denominator (/4), you can add them to get 2/4ths. This can be simplified further to half (1/2) a mile.

5 0

3 years ago

Read 2 more answers

5 x a x 5 x a simplified

Fittoniya [83]

Answer:

5a^2

Step-by-step explanation:

5ax5a=5a^2

3 0

3 years ago

A. Solve the differential equation <img src="https://tex.z-dn.net/?f=y%27%3D2x%20%5Csqrt%7B1-y%5E2%7D%20" id="TexFormula1" title

kirill [66]

$y' = \frac{dy}{dx}$

seperable differential equations will have the form
$\frac{dy}{dx} = F(x) G(y)$

what you do from here is isolate all the y terms on one side and all the X terms on the other
$\frac{dy}{G(y)} = F(x) dx$
just divided G(y) to both sides and multiply dx to both sides

then integrate both sides
$\int \frac{1}{G(y)} dy = \int F(x) dx

$

once you integrate, you will have a constant. use the initial value condition to solve for the constant, then try to isolate x or y if the question asks for it

In your problem,
$G(y) = \sqrt{1-y^2}

F(x) = 2x$

so all you need to integrate is
$\int \frac{1}{\sqrt{1-y^2}} dy = \int 2x dx$