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9966 [12]
3 years ago
9

X^4-7x^2+9 (resolve into factors) Please help me I will mark you as brainliest.

Mathematics
1 answer:
SSSSS [86.1K]3 years ago
5 0

<em><u>Factoring x4-7x2-9 </u></em>

<em><u>Factoring x4-7x2-9 The first term is, x4 its coefficient is 1 .</u></em>

<em><u>Factoring x4-7x2-9 The first term is, x4 its coefficient is 1 .The middle term is, -7x2 its coefficient is -7 .</u></em>

<em><u>Factoring x4-7x2-9 The first term is, x4 its coefficient is 1 .The middle term is, -7x2 its coefficient is -7 .The last term, "the constant", is -9 </u></em>

<em><u>Factoring x4-7x2-9 The first term is, x4 its coefficient is 1 .The middle term is, -7x2 its coefficient is -7 .The last term, "the constant", is -9 Step-1 : Multiply the coefficient of the first term by the constant 1 • -9 = -9 </u></em>

<em><u>Factoring x4-7x2-9 The first term is, x4 its coefficient is 1 .The middle term is, -7x2 its coefficient is -7 .The last term, "the constant", is -9 Step-1 : Multiply the coefficient of the first term by the constant 1 • -9 = -9 Step-2 : Find two factors of -9 whose sum equals the coefficient of the middle term, which is -7 .</u></em>

<em><u>Factoring x4-7x2-9 The first term is, x4 its coefficient is 1 .The middle term is, -7x2 its coefficient is -7 .The last term, "the constant", is -9 Step-1 : Multiply the coefficient of the first term by the constant 1 • -9 = -9 Step-2 : Find two factors of -9 whose sum equals the coefficient of the middle term, which is -7 . -9 + 1 = -8 </u></em>

<em><u>Factoring x4-7x2-9 The first term is, x4 its coefficient is 1 .The middle term is, -7x2 its coefficient is -7 .The last term, "the constant", is -9 Step-1 : Multiply the coefficient of the first term by the constant 1 • -9 = -9 Step-2 : Find two factors of -9 whose sum equals the coefficient of the middle term, which is -7 . -9 + 1 = -8 -3 + 3 = 0 </u></em>

<em><u>Factoring x4-7x2-9 The first term is, x4 its coefficient is 1 .The middle term is, -7x2 its coefficient is -7 .The last term, "the constant", is -9 Step-1 : Multiply the coefficient of the first term by the constant 1 • -9 = -9 Step-2 : Find two factors of -9 whose sum equals the coefficient of the middle term, which is -7 . -9 + 1 = -8 -3 + 3 = 0 -1 + 9 = 8 </u></em>

<h2><em><u>hope </u></em><em><u>I've </u></em><em><u>helped </u></em><em><u>u </u></em><em><u>something</u></em><em><u>.</u></em><em><u>.</u></em><em><u>. </u></em></h2>

<em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>so </u></em><em><u>plz </u></em><em><u>like </u></em><em><u>it </u></em><em><u>and </u></em><em><u>follow </u></em><em><u>me</u></em><em><u>!</u></em><em><u>! </u></em><em><u> </u></em><em><u>♥ </u></em>

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The trigonometric ratio will be Cos(n)=12/13

<h3>What will be the trigonometry ratio?</h3>

Given is a Right triangle LMN with right angle at M i.e. angle M = 90 degrees.

Given are the sides LM = 15, MN = 36, and LN = 39.

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Find dy/dx if y =x^3+5x+2/x²-1
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<u>Differentiate using the Quotient Rule</u> –

\qquad\pink{\twoheadrightarrow \sf \dfrac{d}{dx} \bigg[\dfrac{f(x)}{g(x)} \bigg]= \dfrac{ g(x)\:\dfrac{d}{dx}\bigg[f(x)\bigg] -f(x)\dfrac{d}{dx}\:\bigg[g(x)\bigg]}{g(x)^2}}\\

According to the given question, we have –

  • f(x) = x^3+5x+2
  • g(x) = x^2-1

Let's solve it!

\qquad\green{\twoheadrightarrow \bf \dfrac{d}{dx}\bigg[ \dfrac{x^3+5x+2 }{x^2-1}\bigg]} \\

\qquad\twoheadrightarrow \sf \dfrac{(x^2-1) \dfrac{d}{dx}(x^3+5x+2) - ( x^3+5x+2)  \dfrac{d}{dx}(x^2-1)}{(x^2-1)^2 }\\

\qquad\twoheadrightarrow \sf \dfrac{(x^2-1)(3x^2+5)  -  ( x^3+5x+2) 2x}{(x^2-1)^2 }\\

\qquad\pink{\sf \because \dfrac{d}{dx} x^n = nx^{n-1} }\\

\qquad\twoheadrightarrow \sf \dfrac{3x^4+5x^2-3x^2-5-(2x^4+10x^2+4x)}{(x^2-1)^2 }\\

\qquad\twoheadrightarrow \sf \dfrac{3x^4+5x^2-3x^2-5-2x^4-10x^2-4x}{(x^2-1)^2 }\\

\qquad\green{\twoheadrightarrow \bf \dfrac{x^4-8x^2-4x-5}{(x^2-1)^2 }}\\

\qquad\pink{\therefore  \bf{\green{\underline{\underline{\dfrac{d}{dx} \dfrac{x^3+5x+2 }{x^2-1}}  =  \dfrac{x^4-8x^2-4x-5}{(x^2-1)^2 }}}}}\\\\

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2 years ago
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