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Georgia [21]
3 years ago
5

A soccer balls outer covering is made by stitching together 12 regular pentagons and 20 regular hexagons both regular polygons h

ave a side length of 4cm. The pentagons have an apothem of 3.06cm. To the nearest whole number what is the total surface area of the soccer ball

Mathematics
1 answer:
KengaRu [80]3 years ago
7 0
Http://www.madeiracityschools.org/userfiles/376/Classes/17052/Review%20Worksheet%20Unit%209%20Quiz%2... 

I would use this website. Hope it helps!
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4j + 4j − 6j − j = 12 <br> Solve for J
kherson [118]
J equals 12...........
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3 years ago
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If a track has 219 miles and takes 108 minutes to get there. Is the average speed 104 miles per hour
Tema [17]

Answer:

<em><u>122 miles per hour</u></em><em><u>.</u></em><em><u> </u></em>

Step-by-step explanation:

Time:108 min ÷60 =1.8 hours

Speed = distance /time = 219/1.8 =122 miles per hour.

Hope this helps..

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3 years ago
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Point G is the centroid of triangle abc use the information to find the value of x.
ioda
<span>
2. FG= x +8 and AF = 9x - 6</span>
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3 years ago
Morgan is playing a board game that requires three standard dice to be thrown at one time. Each die has six sides, with one of t
PIT_PIT [208]
The probability of having a 17 is the number of ways of having 17 divided by the number of different possible outcomes.

Ways of having 17:

Die 1     Die 2     Die 3    sum
6            6            5          6+6+5 = 17
6            5            6          6+5+6 = 17
5            6            6          5+6+6 = 17

Those are the only 3 possibilities of having 17 (you can only loose 1 point).

The total number of outcomes are 6*6*6 = 216

So the chances (probability) to win is 3 / 216 = 1/72 = 0.0139 
8 0
3 years ago
1. A farmer divided a field into 1-foot by 1-foot sections and tested soil samples from 32 randomly selected sections in the fie
Ad libitum [116K]
Part A

Answers:
Mean = 5.7
Standard Deviation = 0.046

-----------------------

The mean is given to us, which was 5.7, so there's no need to do any work there.

To get the standard deviation of the sample distribution, we divide the given standard deviation s = 0.26 by the square root of the sample size n = 32
So, we get s/sqrt(n) = 0.26/sqrt(32) = 0.0459619 which rounds to 0.046

================================================

Part B

The 95% confidence interval is roughly (3.73, 7.67)
The margin of error expression is z*s/sqrt(n)
The interpretation is that if we generated 100 confidence intervals, then roughly 95% of them will have the mean between 3.73 and 7.67

-----------------------

At 95% confidence, the critical value is z = 1.96 approximately

ME = margin of error
ME = z*s/sqrt(n)
ME = 1.96*5.7/sqrt(32)
ME = 1.974949
The margin of error is roughly 1.974949

The lower and upper boundaries (L and U respectively) are:
L = xbar-ME
L = 5.7-1.974949
L = 3.725051
L = 3.73
and
U = xbar+ME
U = 5.7+1.974949
U = 7.674949
U = 7.67

================================================

Part C

Confidence interval is (5.99, 6.21)
Margin of Error expression is z*s/sqrt(n)
If we generate 100 intervals, then roughly 95 of them will have the mean between 5.99 and 6.21. We are 95% confident that the mean is between those values.

-----------------------

At 95% confidence, the critical value is z = 1.96 approximately

ME = margin of error
ME = z*s/sqrt(n)
ME = 1.96*0.34/sqrt(34)
ME = 0.114286657
The margin of error is roughly 0.114286657

L = lower limit
L = xbar-ME
L = 6.1-0.114286657
L = 5.985713343
L = 5.99

U = upper limit
U = xbar+ME
U = 6.1+0.114286657
U = 6.214286657
U = 6.21
5 0
3 years ago
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