Answer:
<em><u>122 miles per hour</u></em><em><u>.</u></em><em><u> </u></em>
Step-by-step explanation:
Time:108 min ÷60 =1.8 hours
Speed = distance /time = 219/1.8 =122 miles per hour.
Hope this helps..
<span>
2. FG= x +8 and AF = 9x - 6</span>
The probability of having a 17 is the number of ways of having 17 divided by the number of different possible outcomes.
Ways of having 17:
Die 1 Die 2 Die 3 sum
6 6 5 6+6+5 = 17
6 5 6 6+5+6 = 17
5 6 6 5+6+6 = 17
Those are the only 3 possibilities of having 17 (you can only loose 1 point).
The total number of outcomes are 6*6*6 = 216
So the chances (probability) to win is 3 / 216 = 1/72 = 0.0139
Part A
Answers:
Mean = 5.7
Standard Deviation = 0.046
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The mean is given to us, which was 5.7, so there's no need to do any work there.
To get the standard deviation of the sample distribution, we divide the given standard deviation s = 0.26 by the square root of the sample size n = 32
So, we get s/sqrt(n) = 0.26/sqrt(32) = 0.0459619 which rounds to 0.046
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Part B
The 95% confidence interval is roughly (3.73, 7.67)
The margin of error expression is z*s/sqrt(n)
The interpretation is that if we generated 100 confidence intervals, then roughly 95% of them will have the mean between 3.73 and 7.67
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At 95% confidence, the critical value is z = 1.96 approximately
ME = margin of error
ME = z*s/sqrt(n)
ME = 1.96*5.7/sqrt(32)
ME = 1.974949
The margin of error is roughly 1.974949
The lower and upper boundaries (L and U respectively) are:
L = xbar-ME
L = 5.7-1.974949
L = 3.725051
L = 3.73
and
U = xbar+ME
U = 5.7+1.974949
U = 7.674949
U = 7.67
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Part C
Confidence interval is (5.99, 6.21)
Margin of Error expression is z*s/sqrt(n)
If we generate 100 intervals, then roughly 95 of them will have the mean between 5.99 and 6.21. We are 95% confident that the mean is between those values.
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At 95% confidence, the critical value is z = 1.96 approximately
ME = margin of error
ME = z*s/sqrt(n)
ME = 1.96*0.34/sqrt(34)
ME = 0.114286657
The margin of error is roughly 0.114286657
L = lower limit
L = xbar-ME
L = 6.1-0.114286657
L = 5.985713343
L = 5.99
U = upper limit
U = xbar+ME
U = 6.1+0.114286657
U = 6.214286657
U = 6.21