Answer:
p(2) =147 and p(4) = 1791
Step-by-step explanation:
We are given p(x)= 6x^4 + 4x^3 – 3x^2 + 8x + 15.
Now we need to find value of p(2) and p(4)
Put x =2,
p(2) = 6(2)^4 + 4(2)^3 – 3(2)^2 + 8(2) + 15
p(2) = 6(16)+4(8)-3(4)+8(2)+15
p(2) = 96+32-12+16+15
p(2) = 147
Now put x = 4
p(4) = 6(4)^4 + 4(4)^3 – 3(4)^2 + 8(4) + 15
p(4) = 6(256)+4(64)-3(16)+8(4)+15
p(4) = 1536+256-48+32+15
p(4) = 1791
hope this helps-------------
X=8 would you like me to explain why?
15.
0.20*x = 0.01*x + 38 => 0.19*x = 38 =>( 19/100 )*x = 38 => x = 3800/19 => x = 200.
Answer:
(x, y) ≈ (2.848, -19.241)
Step-by-step explanation:
I find it much easier to work with the problem statement when math expressions are written using numbers and symbols. We assume you have ...
-4x +15y = -300
20x +4y = -20
Dividing the second equation by 4 and subtracting the x-term gives ...
y = -5-5x
Substituting that into the first equation, we get ...
-4x +15(-5-5x) = -300
-79x -75 = -300
x = -225/-79 = 2 67/79 ≈ 2.8481
Substituting this into the equation for y gives ...
y = -5(x +1) = -5(3 67/79) = -19 19/79 ≈ -19.2405
The approximate solution is ...
(x, y) = (2.8481, -19.2405)