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3 years ago

The value of x on the triangle

Mathematics

1 answer:

Marianna [84]3 years ago

3 0

X would equal 10.4 hehehe

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How to work out the number x is reduced by 25% and then halved?

Taya2010 [7]

Find a quarter of x (because 25% is 1/4 of 100%) and take it away (because we're decreasing) from the original number (x)
then half the answer
Hope this helps :)

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3 years ago

Find the MAD:<br>58, 38, 54, 48, 26, 36

trasher [3.6K]

Answer:

10.166666666667

Step-by-step explanation:

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3 years ago

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The equation (x + 11)^2 + (y – 27)^2 = 2.25, with units in yards, represents a circular fountain in a park. The park entrance ma

LenKa [72]

Answer:

Step-by-step explanation:

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3 years ago

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How to solve this integration problem? the answer should be -π/12

ivann1987 [24]

$\displaystyle\int_{-1}^{-\sqrt2/2}\frac{\mathrm dy}{y\sqrt{4y^2-1}}$

Try setting $y=\dfrac12\sec t$ , so that $\mathrm dy=\dfrac12\sec t\tan t\,\mathrm dt$ . The interval then changes from $-1\le y\le-\dfrac{\sqrt2}2$ to $\dfrac{2\pi}3\le t\le \dfrac{3\pi}4$ .

Now, the integral is

$\displaystyle \int_{2\pi/3}^{3\pi/4} \frac{\dfrac12\sec t\tan t}{\dfrac12\sec t\sqrt{4\left(\dfrac12\sec t\right)^2-1}}\,\mathrm dt=\int_{2\pi/3}^{3\pi/4}\frac{\tan t}{\sqrt{\sec^2t-1}}\,\mathrm dt$

The Pythagorean identity lets you reduce the denominator:

$\sqrt{\sec^2t-1}=\sqrt{\tan^2t}=|\tan t|$

Since $\tan t$ for the given interval, you have $|\tan t|=-\tan t$ , which means the integral is equal to

$\displaystyle\int_{2\pi/3}^{3\pi/4}\frac{\tan t}{-\tan t}\,\mathrm dt=-\int_{2\pi/3}^{3\pi/4}\mathrm dt=-\dfrac\pi{12}$

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4 years ago

(4, 2); slope = 3<br> How do you do this problem and show work

damaskus [11]

Use the point-slope formula.

y - y_1 = m(x - x_1)

Let m = 3

Let y_1 = 2

Let x_1 = 4

We now plug and chug.

y - 2 = 3(x - 4)

y - 2 = 3x - 12

We now isolate y.

y = 3x - 12 + 2

y = 3x - 10

6 0

3 years ago