Question

∠A is an acute angle in a right triangle.

Answer 1

Answer: sinA=8/17 to solve for this you must use Pythagorean theorem and solve for the unknown side. Once you do that you can use SohCahToa to find the fraction that you need to solve for the angle.

Answer 2

Answer:    sinA= 8/17

Step-by-step explanation:  since, sin²A+cos²A=1

                        ⇒  sin²A= 1-cos²A

                        ⇒ sin²A= 1- $(\frac{15}{17}) ^2$

                        ⇒ sin²A=  1- $\frac{15^2}{17^2}$

                        ⇒  sin²A= $\frac{17^2-15^2}{17^2}$

                        ⇒   sin²A= $\frac{64}{17^2}$

                         ⇒ sin²A= $\frac{8^2}{17^2}$

                         ⇒ sin²A= $(\frac{8}{17}) ^2$

                        ⇒  sinA=$\frac{8}{17}$