Let x = first plane's speed.
We have the equation:
2 hours * x km/h + 1.5 hours * (x+60) km/h = 3135 km.
3.5 hours*x km/h + 90 km = 3135km
3.5hours*x km/h = 3045km
x = 870 km/h.
The first plane is traveling at 870 km/h, therefore since it is 60 km/h faster, the second plane is traveling at 930 km/h.
x + 3y <= 191
x = children
y = adults (x3)
So adding those two up must be either less than or equal to 191, as that is all the Chef made.
Answer:
=−5x2+18x−13
Step-by-step explanation:
Let's simplify step-by-step.
x2−1−3(2x−2)(x−2)
Distribute:
=x2+−1+−6x2+18x+−12
Combine Like Terms:
=x2+−1+−6x2+18x+−12
=(x2+−6x2)+(18x)+(−1+−12)
=−5x2+18x+−13
Answer:
=−5x2+18x−13
Using the y = mx + b formula
C = 225s + 3500
Then to transport 19 tons
C = 225(19) + 3500
C = 4275 + 3500
C = 7775
Sine (28) = opposite / hypotenuse =
0.46947 = opposite / 28
opposite = 0.46947 * 28
<span><span><span>opposite side = 13.14516
</span>
</span>
</span>
cosine (28) = adjacent / hypotenuse =
0.88295 = adjacent / 28
adjacent = 28 * .88295
<span><span><span>adjacent side = 24.7226
</span>
Double Check
</span>
</span>
<span>13.14516^2 + 24.7226^2 = 28^2
</span>
<span>
<span>
<span>
172.7952314256
</span>
</span>
</span>
+
<span>
<span>
<span>
611.20695076
</span>
</span>
</span>
= 784
<span>
<span>
<span>
784.0021821856
</span>
</span>
</span>
= 784
Correct to 5 significant figures
