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Whitepunk [10]
3 years ago
5

2010 0.15

Mathematics
1 answer:
aniked [119]3 years ago
4 0

Answer:

it is a :) hope this helped :)

Step-by-step explanation:

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Harold bought 3 pounds of red apples and 4.2 pounds of green apples from a grocery store, where both kinds of apples are $1.75 a
Lelechka [254]
The answer is 11.6
add 3+4.2= 7.2 times 1.75
4 0
2 years ago
Find the exact length of the curve. x=et+e−t, y=5−2t, 0≤t≤2 For a curve given by parametric equations x=f(t) and y=g(t), arc len
Rama09 [41]

The length of a curve <em>C</em> parameterized by a vector function <em>r</em><em>(t)</em> = <em>x(t)</em> i + <em>y(t)</em> j over an interval <em>a</em> ≤ <em>t</em> ≤ <em>b</em> is

\displaystyle\int_C\mathrm ds = \int_a^b \sqrt{\left(\frac{\mathrm dx}{\mathrm dt}\right)^2+\left(\frac{\mathrm dy}{\mathrm dt}\right)^2} \,\mathrm dt

In this case, we have

<em>x(t)</em> = exp(<em>t</em> ) + exp(-<em>t</em> )   ==>   d<em>x</em>/d<em>t</em> = exp(<em>t</em> ) - exp(-<em>t</em> )

<em>y(t)</em> = 5 - 2<em>t</em>   ==>   d<em>y</em>/d<em>t</em> = -2

and [<em>a</em>, <em>b</em>] = [0, 2]. The length of the curve is then

\displaystyle\int_0^2 \sqrt{\left(e^t-e^{-t}\right)^2+(-2)^2} \,\mathrm dt = \int_0^2 \sqrt{e^{2t}-2+e^{-2t}+4}\,\mathrm dt

=\displaystyle\int_0^2 \sqrt{e^{2t}+2+e^{-2t}} \,\mathrm dt

=\displaystyle\int_0^2\sqrt{\left(e^t+e^{-t}\right)^2} \,\mathrm dt

=\displaystyle\int_0^2\left(e^t+e^{-t}\right)\,\mathrm dt

=\left(e^t-e^{-t}\right)\bigg|_0^2 = \left(e^2-e^{-2}\right)-\left(e^0-e^{-0}\right) = \boxed{e^2-\frac1{e^2}}

5 0
2 years ago
Can someone hello son please make sure it’s right :)
Sedaia [141]

Answer: x= -12

Step-by-step explanation:

These are corresponding angles which means they are the same. X+62= 50. Subtract 62 from both sides. X= -12

4 0
2 years ago
Read 2 more answers
There are 1560 students enrolled at greenwood middle school if 85% of these ride the bus how many does not ride the bus
loris [4]

Answer: 1326 students won't come to school

Step-by-step explanation:

All you have to do is find out 85% of 1560 which is 1326 students!

4 0
3 years ago
Enrollment in a photography class increased from 25 to 35 students. What was the percent of increase in enrollment?
DaniilM [7]
About 29%.
35 - 25 = 10, or the amount of change
10 / 35 = .285, or the amount of change over total
3 0
3 years ago
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