Let me tell you the process so that you get to the answer
Remember first that the area of a regular polygon with x sides has each of them a length which can be represented by y
<span>A = 1/4 * xy^2 * Cot(180/x) </span>
<span>The purpose is to solve for y, so we get </span>
<span>y^2 = 4A/(xCot(180/x)) </span>
<span>y = √(4A/(xCot(180/x)))
The thing we need to change is A in the previous formula and with that we can use the equaation to be a constant. This could be represented by Z
</span><span>Z = √(4/(xCot(180/x)))
so
</span><span>Y = Z√A
</span><span>If we increase area by a factor s, y increases by a factor of √x.
</span>So if you want to know the triple then you need to increase it by <span> √3 </span> <span> </span>
Given:
Mean, μ = 196
Std. dev., σ = 22
A sample size of 50 (> 30) is large enough to provide meaningful data.
The random variable is x = 200.
The z-score is
z = (x - μ)/σ = (200 - 196)/22 = 0.1818
From normal distribution tables, obtain
Prob(X < 200) = 0.572 = 57.2%
Answer: 57.2%
Answer:
Domain is 8 to 15 broomsticks
Range is 1,200 to 2,250 Galleons
Step-by-step explanation:
Here, when we talk of the domain, we are simply referring to the range of values of the number of broomsticks to be bought which is between 8 and 15
When we talk of the range, we are talking of the amount these broomsticks will cost
The cost for 8 broomsticks will be 8 * 150 = 1,200 Galleons
15 broomsticks will cost 15 * 150 = 2,250 Galleons
The range here will thus be 1,200 Galleons to 2,250 Galleons
Answer:
No, the reference point selected for the properties of a substance does't have any effect on thermodynamic analysis.
Step-by-step explanation:
Consider the provided information.
We need to determine that the reference point selected for the properties of a substance have any effect on thermodynamic analysis.
The answer for this question is No.
The reference point selected for the properties of a substance does't have any effect on thermodynamic analysis.
Because in thermodynamic analysis we are deal with the change in the properties.
If we are doing calculation, the reference state chosen is irrelevant as long as we use values in a single consistent array of tables and charts.
Hence, The reference point selected for the properties of a substance does't have any effect on thermodynamic analysis.
If you would like to solve the following system, you can calculate this using the following steps:
y = x - 20
y = 6 * x
_________
6 * x = x - 20
6 * x - x = -20
5 * x = -20 /5
x = -4
y = 6 * x = 6 * (-4) = -24
If you would like to solve the following system, you can calculate this using the following steps:
y = x + 20
y = 6 * x
_________
6 * x = x + 20
6 * x - x = 20
5 * x = 20 /5
x = 4
y = 6 * x = 6 * 4 = 24
