What is the sum measure of x and y??

F(x) = x^2+3; g(x) = square root of x-2 find f(g(x))

Anettt [7]

F(g(x)) = x + 1 . Just replace square root of x-2 to x in f(x)

5 0

3 years ago

Hunter-Best [27]

Answer:

a.The ratio of the heights is the square roots of the both of them √64 and √144

which is 8 and 12

b.To find the height of the larger prism you use the ratio of the heights,in a ratio and proportion

8 - 49

12-x

8x/8=588/8

x=73.5

I hope this helps

4 0

3 years ago

rectangular cake pans X and Y are similar. The ratio of the width of the pan X to the width of pan Y is 3 : 4. The length of pan

Vikki [24]

We have two rectangles such as:
Rectangle 1 = X
Rectangle 2 = Y
Where the ratio of the two is:
Ratio = X / Y = 3/4
If x length is 10, we can solve for y length such as:
10 /Y length =3/4
Y length = 40/3 = 13.33

If x width is 5, then we can solve for y width such as:
5/y width = 3/4
y width = 20/3 = 6.67

The Perimeter of Pan Y is shown below:
Y perimeter = 2(6.67) + 2(13.33)
Y perimeter = 40

The answer is 40 inches.

3 0

3 years ago

Name the smallest angle of ABC. The diagram is not to scale.<br> с<br> 11<br> 10<br> B

Mrac [35]

Answer:

uhhhh Where's a picture?

6 0

2 years ago

A machine that puts corn flakes into boxes is adjusted to put an average of 15.6 ounces into each box, with standard deviation o

Anastaziya [24]

Answer:

$\chi^2 =\frac{15-1}{0.0676} 0.1521 =31.5$

$p_v =P(\chi^2_{14} >31.5)=0.0047$

If we compare the p value and the significance level assumed of 0.05 we see that $p_v$ so on this case we have enough evidence in order to reject the null hypothesis at the significance level provided. And that means that the population variance is significantly higher than 0.26^2=0.0676.

Step-by-step explanation:

Notation and previous concepts

A chi-square test is "used to test if the variance of a population is equal to a specified value. This test can be either a two-sided test or a one-sided test. The two-sided version tests against the alternative that the true variance is either less than or greater than the specified value"

$n=15$ represent the sample size

$\alpha$ represent the confidence level

$s^2 =0.39^2 =0.1521$ represent the sample variance obtained

$\sigma^2_0 =0.26^2 =0.0676$ represent the value that we want to test

Null and alternative hypothesis

On this case we want to check if the population variance specification is violated, so the system of hypothesis would be:

Null Hypothesis: $\sigma^2 \leq 0.0676$

Alternative hypothesis: $\sigma^2 >0.0676$

Calculate the statistic

For this test we can use the following statistic:

$\chi^2 =\frac{n-1}{\sigma^2_0} s^2$

And this statistic is distributed chi square with n-1 degrees of freedom. We have eveything to replace.

$\chi^2 =\frac{15-1}{0.0676} 0.1521 =31.5$

Calculate the p value

In order to calculate the p value we need to have in count the degrees of freedom , on this case df=15-1=14. And since is a right tailed test the p value would be given by:

$p_v =P(\chi^2_{14} >31.5)=0.0047$

In order to find the p value we can use the following code in excel:

"=1-CHISQ.DIST(31.5,14,TRUE)"

Conclusion

If we compare the p value and the significance level assumed of 0.05 we see that $p_v$ so on this case we have enough evidence in order to reject the null hypothesis at the significance level provided. And that means that the population variance is significantly higher than 0.26^2=0.0676.

4 0

2 years ago