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garik1379 [7]
4 years ago
6

Simplify the following question given above

Mathematics
1 answer:
zysi [14]4 years ago
6 0

Answer:

a) 5⁵ = 3125

Step-by-step explanation:

<u><em>Explanation:-</em></u>

<em>Given  </em>

<em>                   </em>\frac{3^{-5} X 10^{-5} X 125 }{5^{-7} X 6 ^{-5}  }<em></em>

<em>on simplification , we get</em>

<em>          =        </em>\frac{3^{-5} X (5 X 2)^{-5} X(5)^{3}  }{5^{-7} X (3 X 2) ^{-5}  }<em></em>

<em>By using algebraic formula </em>

<em>(ab)ⁿ = aⁿ b ⁿ      </em>

<em>   </em>

<em>           = </em>\frac{3^{-5} X (5)^{-5} X (2)^{-5} X(5)^{3}  }{5^{-7} X{(3^{-5} } )(2) ^{-5}  }<em></em>

<em>after cancellation , we get</em>

<em></em>

<em>        =    </em>\frac{ (5)^{-5} X(5)^{3}  }{5^{-7}  }<em>  </em>

<em>       =   </em>(5)^{-5} X(5)^{3} X (5)^{7}<em></em>

<em>       = 5⁻⁵⁺³⁺⁷</em>

<em>      = 5⁵</em>

<em>     = 3125</em>

<u><em>final answer:-</em></u>

<em></em>\frac{3^{-5} X 10^{-5} X 125 }{5^{-7} X 6 ^{-5}  } = 3125<em></em>

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kodGreya [7K]

In -3,-1,0,3 is -3 and 3 pair of numbers has a sum of 0.

To find the possible pair of integers in each section, we apply the notion of integers. If it's possible, choose any two variables from a set of numbers and look for relationships between them.

Positive and negative counting numbers, as well as zero, make up integers. Think about each pair of integers or numbers whose sum will be zero. Discover this particular pair. There are numerous ways to obtain two integers whose total is zero. However, the number must match the opposing sign exactly.

Given numbers are -3,-1,0,3

From the given sum of the numbers, -3 and 3  are zero.

-3+3=0

To learn more about integers refer the link:

brainly.com/question/12399107

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2 years ago
A contractor has submitted bids on three state jobs: an office building, a theater, and a parking garage. State rules do not all
german

Answer:

The following are the answer to this question:

Step-by-step explanation:

In the given question the numeric value is missing which is defined in the attached file please fine it.  

Calculating the probability of the distribution for x:

\to f(x) = 0.19\  for \ x=14\\\\\to  f(x) = 0.29 \ for\ x=7\\\\\to f(x) = 0.38\  for \ x=1\\\\\to f(x)=0.14 \ for \ x=0\\

The formula for calculating the mean value:

\bold{ E(X)= x \times f(x)}

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\bold{E(X^2) = x^2 \times f(x)}

           =14^2 \times 0.19+7^2 \times 0.29+1^2 \times 0.38+0^2 \times 0.14 \\\\=196 \times 0.19+ 49 \times 0.29+1 \times 0.38+0 \times 0.14\\\\= 37.24+ 14.21+ 0.38+0 \\\\=51.83

use formula for calculating the Variance:

\to \bold{\text{Variance}= E(X^2) -[E(X)]^2}

                  = 51.83 - (5.07)^2\\\\= 51.83 -  25.70\\\\=26.13

calculating the value of standard deivation:

Standard Deivation (SD) = \sqrt{Variance}

                                          = \sqrt{26.13} \\\\=5.111

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