Question

Snowy's Snow Cones has a special bubble gum snow cone on sale. The cone is a regular snow cone that has a spherical piece of bubble gum nested at the bottom of the cone. The radius of the snow cone is 6 inches, and the height of the cone is 10 inches. If the diameter of the bubble gum is 1.5 inches, which of the following can be used to calculate the volume of the cone that can be filled with flavored ice? 1 over 3(3.14)(102)(6) − 4 over 3(3.14)(1.53) 1 over 3(3.14)(62)(10) − 4 over 3(3.14)(1.53) 1 over 3(3.14)(102)(6) − 4 over 3(3.14)(0.753) 1 over 3(3.14)(62)(10) − 4 over 3(3.14)(0.753)

Answer 1

Hello again!! (go to your messages if you don't remember me)

First, calculate the volume of the empty cone.
V₁ = (1/3)π*(6 in)²*(10 in) = 120π in³

Calculate the volume of the sphere.
V₂ = (4/3)π*(1.5 in)³ = 4.5π in³

The volume that can be filled with flavored ice is 
V = V₁ - V₂ = 115.5π in³ = 362.85 in³

Answer:
The volume is 115.5π in³ or 362.9 in³ (nearest tenth)

Hope this helps!! Let me know if you have ANY questions.

Answer 2

Answer:

The radius of the snow cone is 6 inches, and the height of the cone is 10 inches.

The diameter of the bubble gum is 1.5 inches.

The volume of cone is given by = $\frac{\pi r^{2} h}{3}$

So, volume of cone is =  $\frac{3.14*6*6* 10}{3}$= 376.80 cubic inches

And as the bubble gum is a sphere of diameter 1.5 inches.

So, radius is $\frac{1.5}{2}= 0.75$ inches

Volume of sphere is given by = $\frac{4}{3} \pi r^{3}$

Volume becomes: $\frac{4}{3} *3.14*0.75*0.75*0.75$

= 1.766 cubic inches

So, volume of the cube that can be filled with flavored ice will be =

$376.80-1.766=375.03$ cubic inches.