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Solnce55 [7]
3 years ago
14

A 2-column table with 5 rows. Column 1 is labeled Days with entries 1, 2, 3, 4, 5. Column 2 is labeled miles with entries 6, 12,

18, 24, 30.
Which scenario matches the relationship shown in the table?
Sakura walked 6 miles yesterday.
Sakura walks 6 miles every day.
Sakura walked less than 6 miles.
Sakura walked 1 day in 6 miles.
Mathematics
2 answers:
Lera25 [3.4K]3 years ago
8 0

Answer:

Sakura walks 6 miles every day.  

Brainly plz :))

ZanzabumX [31]3 years ago
3 0
I believe that it is “Sakura walks 6 miles every day”
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What is ​ BC ​ ? Enter your answer in the box. units
EleoNora [17]

Answer:

25

Step-by-step explanation:

I'll explain in detail for those of you that want to know.


You know that since angles B and C are congruent to each other that this triangle is an isosceles triangle. Therefore, sides AB and AC are congruent to each other because that is a property of an isosceles triangle.  

To solve for x, place the expressions of sides AB and AC equal to each other and solve for the unknown variable.

4x + 1 = 2x + 23

You should get that x = 11.  

Substitute x = 11 into the expression for side BC to solve for the length of that side.  

f(11) = 3(11) - 8  

f(11) = 25  

Thus, length of side BC is 25 units.


Use this way of solving for all your future questions. It's really simple :)

5 0
4 years ago
What is the product of 5 and x
andrey2020 [161]
I believe the product is 5x. Hope that helps :)
7 0
3 years ago
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8 is 32 times as many as 4
Ber [7]
What’s the question on this??? I’m confused. Please lmk so I can help you get the right answers :)
6 0
3 years ago
The velocity of a particle moving back and forth on a line is vequalsStartFraction ds Over dt EndFraction equals6 sine (2 t )Sta
max2010maxim [7]

Answer:

s = 6 m

Step-by-step explanation:

The value of the velocity v is given as:

v = \frac{ds}{dt} = 6 sin(2t) m/s

To find s, we have to integrate and apply the initial values of s = o when t = 0:

\frac{ds}{dt} = 6 sin(2t)\\\\\int\limits^s_0 {ds} = \int\limits^t_0 {6sin(2t)} \, dt\\\\s|^s_o = -3cos(2t)|^t_o\\\\s - 0 = -3cos(2t) -(-3cos(0))\\\\s = -3cos(2t) + 3(1)\\\\s = -3cos(2t) + 3

When t = π/2, s will be:

s = -3cos(2 * π/2) + 3

s = -3cos(π) + 3

s = -3(-1) + 3

s = 3 + 3

s = 6 m

4 0
4 years ago
In parallelogram ABCD, AE=x^2-6 and CE=5x what is the value of x ? What is AC?
lutik1710 [3]

Answer:

see explanation

Step-by-step explanation:

The diagonals of a parallelogram bisect each other, hence

AE = EC, that is

x² - 6 = 5x ( subtract 5x from both sides )

x² - 5x - 6 = 0 ← in standard form

(x - 6)(x + 1) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 6 = 0 ⇒ x = 6

x + 1 = 0 ⇒ x = - 5

However x > 0 ⇒ x = 6

AC = x² - 6 + 5x = 6² - 6 + 5(6) = 36 - 6 + 30 = 60

3 0
3 years ago
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