How many solutions does this system have?
2 answers:
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Answer : The amount of margarine needed is 1 kg.
Step-by-step explanation :
First we have to convert volume of syrup from mL to L.
Conversion used:
1 L = 1000 mL
or, 1 mL = 0.001 L
So, 225 mL = 0.225 L
Now we have to calculate the amount of margarine needed.
As, 0.225 L of syrup needed 150 g of margarine
So, 1.8 L of syrup needed of margarine
Amount of margarine needed = 1000 g = 1 kg (1 kg = 1000 g)
Therefore, the amount of margarine needed is 1 kg.
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