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3 years ago

How many solutions does this system have?

Mathematics

2 answers:

Andrew [12]3 years ago

8 0

That system has D. no solutions

faust18 [17]3 years ago

4 0

Answer: no solution

Step-by-step explanation:

Solve by substitution

Divide each term by 2 and simplify.

Replace all occurrences of y with the solution found by solving the last equation for y. In this case, the value substituted is 5x+1.

Solve for x in the second equation.

Since −1≠3, there are no solutions.

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I’ve tried to work this out but I can’t get it figured out. Can someone help me

Bas_tet [7]

G(2) = -4(2) = -8
f(g(2)) = (-8)^2 = 64

answer
64

5 0

3 years ago

A computer chess game and a human chess champion are evenly matched. They play twelve games. Find probabilities for the followin

sleet_krkn [62]

Answer:

The probability that they each win six games is 0.225.

Step-by-step explanation:

Given : A computer chess game and a human chess champion are evenly matched. They play twelve games.

To find : The probability that they each win six games?

Solution :

Applying binomial distribution,

Here n=12 and p=0.5

$P(X=k)=\frac{n!}{k!(n-k)!}\times p^k\times (1-p)^{n-k}$

The probability that they each win six games is k=6.

$P(X=6)=\frac{12!}{6!(12-6)!}\times 0.5^6\times (1-0.5)^{12-6}$

$P(X=6)=\frac{12\times 11\times 10\times 9\times 8\times 7\times 6!}{6\times 5\times 4\times 3\times 2\times 6!}\times 0.015625\times 0.015625$

$P(X=6)=11\times 2\times 3\times 2\times 7\times 0.015625\times 0.015625$

$P(X=6)=0.225$

Therefore, The probability that they each win six games is 0.225.

3 0

3 years ago

the area of a rectangular volleyball court is 1800 square feet the courts length is twice it width write a system of equations t

Marianna [84]

Answer:

The dimensions of the rectangular volleyball court are 60 ft x 30 ft

Step-by-step explanation:

Let

x ----> the length of rectangular volleyball court

y ---> the width of the rectangular volleyball court

we know that

The area of the rectangular volleyball court is equal to

$A=xy$

$A=1,800\ ft^2$

$1,800=xy$ ----> equation A

$x=2y$ -----> equation B

substitute equation B in equation A

$1,800=(2y)y$

$1,800=2y^2$

Solve for y

Simplify

$900=y^2$

take square root both sides

$y=30\ ft$

Find the value of x

$x=2y$

substitute the value of y

$x=2(30)=60\ ft$

therefore

The dimensions of the rectangular volleyball court are 60 ft x 30 ft

7 0

3 years ago

I need help on what the area of the shape is because they didn’t tell us how to find it

Leto [7]

Answer:

The area of the shape (trapezoid) is 55 square feet.

Step-by-step explanation:

The formula to get the area of a trapezoid is $((b_{1} +b_{2} )/2)*h$ . b1 is one of the bases, b2 is the other and h is the height.

First, you need to find the average of the bases:

(15+7=22)/2=11

Then, you multiply that by the height.

11*5=55

Lastly, you add the units.

55 square feet is the answer

8 0

3 years ago

How to simplify -12 divided by 3•(-8+(-4) to the seccond power-6)+2

ehidna [41]

-12/3•(-8(-4)^2-6)+2 Original Equation
-12/3•(-8+16-6)+2 Simplify the (-4)^2
-12/3•(2)+2 Simplify everything inside the equation
-8+2 Using PEMDAS, you multiply -12/3•(2)
-6 You add from there

7 0

3 years ago

How many solutions does this system have?​

How many solutions does this system have?