Using the normal distribution, it is found that 58.97% of students would be expected to score between 400 and 590.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean 
and standard deviation 
is given by:
- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
The mean and the standard deviation are given, respectively, by:
The proportion of students between 400 and 590 is the <u>p-value of Z when X = 590 subtracted by the p-value of Z when X = 400</u>, hence:
X = 590:
Z = 0.76
Z = 0.76 has a p-value of 0.7764.
X = 400:
Z = -0.89
Z = -0.89 has a p-value of 0.1867.
0.7764 - 0.1867 = 0.5897 = 58.97%.
58.97% of students would be expected to score between 400 and 590.
More can be learned about the normal distribution at brainly.com/question/27643290
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Answer:
c
Step-by-step explanation:
Answer:
w > -14
Step-by-step explanation:
Divide both sides by -6.
-6w/-6 = w
84/-6 = 14
Since it's an equality, if the coefficient of the variable is negative, when you divide the sign flips to the opposite.
Answer:
1. (n + 3)(5n + 8)
2. (x - 4)(7x - 4)
3. (k + 8)(7k + 1)
Step-by-step explanation:
1. We have to factorize 5n² + 23n + 24.
Now, 5n² + 23n + 24
= 5n² + 15n + 8n + 24
= 5n (n + 3) + 8 (n + 3)
=(n + 3)(5n + 8) (Answer)
2. We have to factorize 7x² - 32x + 16
Now, 7x² - 32x + 16
= 7x² - 28x - 4x + 16
= 7x (x - 4) - 4 (x - 4)
= (x - 4)(7x - 4) (Answer)
3. We have to factorize 7k² + 57k + 8
Now, 7k² + 57k + 8
= 7k² + 56k + k + 8
= 7k (k + 8) + 1 (k + 8)
= (k + 8)(7k + 1) (Answer)
So, let's make these two values improper fractions so they're easier to work with. 
So, to get the rate he grew in those months we have:
And to get the rate he grew in one month we have to divide both our numerator and our denominator by 21 to get:
aka he grew 1.24 inches in a month.
