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Ipatiy [6.2K]
3 years ago
11

X/10=6/15 what is x?

Mathematics
2 answers:
Ivahew [28]3 years ago
5 0

Answer:

Step-by-step explanation:

\frac{x}{10} = \frac{6}{15}

Cross-multiplying will give us the following:

15x = 60

Dividing both sides by 15 will give us our answer:

x = 4

Gelneren [198K]3 years ago
5 0

Answer:x=4

Step-by-step explanation:

X/10=6/15

Cross multiply

15x=60

x=4

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The rate of change of the number of mountain lions N(t) in a population is directly proportional to 725 - N(t), where t is the t
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Answer:

a) The implied differential equation is \frac{dN}{725 - N} = kdt

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c) The particular equation is N = 725 - 325 e^{-0.49t}

d) The population when t = 5, N(5) = 697 = 700( to the nearest 50)

Step-by-step explanation:

The rate of change of N(t) can be written as dN/dt

According to the question, \frac{dN}{dt} \alpha (725 - N(t))

\frac{dN}{dt} = k (725 - N)\\\frac{dN}{725 - N} = kdt

Integrating both sides of the equation

\int {\frac{1 }{725 - N}} \, dN  = \int {k} \, dt\\- ln (725 - N) = kt + C\\ ln (725 - N) = -(kt + C)\\725 - N = e^{-(kt + C)} \\725 - N = e^{-kt} * e^{-C} \\725 - N = C e^{-kt}\\N = 725 - C e^{-kt}

When t = 0, N = 400

400 = 725 - C e^{-k*0}\\400 = 725 - C\\C = 725 - 400\\C = 325

When t = 3,  N = 650

650 = 725 - (325 * e^{-3k})\\325 * e^{-3k} = 75\\e^{-3k} = 75/325\\e^{-3k} = 0.23\\-3k = ln 0.23\\-3k = -1.47\\k = 1.47/3\\k = 0.49

The equation for the population becomes:

N = 725 - 325 e^{-0.49t}

At t = 5, the population becomes:

N = 725 - 325 e^{-0.49*5}\\N = 725 - 325 e^{-2.45}\\N = 696.95\\N(5) = 697

N(5) = 700 ( to the nearest 50)

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