Answer:
70.34 litres
Explanation:
Using ideal gas law equation;
PV = nRT
Where;
P = pressure (atm)
V = volume (L)
n = number of moles (mol)
R = gas law constant (0.0821 Latm/molK)
T = temperature (K)
According to the information given in the question;
n = 3 moles
V = ?
P = 105.2 KPa = 105.2/101 = 1.04atm
T = 24.0°C = 24 + 273 = 297K
Using PV = nRT
1.04 × V = 3 × 0.0821 × 297
1.04V = 73.15
V = 73.15 ÷ 1.04
V = 70.34 litres.
Easy!
All you have to do is look at the formula.
Lead Sulfide is PbS
Lead Oxide is PbO
Sulfur Dioxide is SO₂
Oxygen is O₂
You would need to balance out the equation, so it would be PbS + O₂ --> PbO + SO₂.
We can balance this out with the following. 2PbS + 2O₂ --> 2PbO + SO₂.
So 0.500 moles of oxygen would be the same conversion rate for PbO so it would also be 0.500 moles of lead oxide (PbO)
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