Answer: as a relatively high boiling point high specific heat connotation adhesion and density
Explanation:
water molecules are polar so they form hydrogen bonds this gives water unique properties
Answer:
What will determine the number of moles of hydronium in an aqueous solution of a strong monoprotic acid? The amount of acid that was added.
Explanation:
Pb (lead) is in the 6th period
(please give brainliest if this helped you)
Answer:
We expect the enthalpies of combustion of two isomers to be different.
The molecular formular of the two molecules are very similar.
So the balanced chemical equation for the two combustion reactions are the same.
Explanation:
In calculation of the combustion enthalpiesfrom the isomers of the products and reactant.
The difference will be in the standard enthalpies of formation of the two combustion products.
The rod-shaped n- octane has vibrational and rotational motion possible more than the almost spherical neoprene.
Answer:
1.930 * 10⁻⁹ mg of Mn⁺² are left unprecipitated.
Explanation:
The reaction that takes place is:
Mn⁺² + S⁻² ⇄ MnS(s)
ksp = [Mn⁺²] [S⁻²]
If the pksp of MnS is 13.500, then the ksp is:
From the problem we know that [S⁻²] = 0.0900 M
We use the ksp to calculate [Mn⁺²]:
3.1623*10⁻¹⁴= [Mn⁺²] * 0.0900 M
[Mn⁺²] = 3.514 * 10⁻¹³ M.
Now we can calculate the mass of Mn⁺², using the volume, concentration and atomic weight. Thus the mass of Mn⁺² left unprecipitated is:
3.514 * 10⁻¹³ M * 0.1 L * 54.94 g/mol = 1.930 * 10⁻¹² g = 1.930 * 10⁻⁹ mg.
