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Harrizon [31]
3 years ago
9

Copper(i) ions in aqueous solution react with nh3(aq) according to

Chemistry
1 answer:
Vlada [557]3 years ago
6 0
The complete question is; copper (i) ions in aqueous solutions react with NH3(aq) according to;
 Cu +2NH3 = Cu(NH3)2    Kt= 6.3 × 10^10
Calculate K
Cu + 2NH3 = Cu(NH3)2
kf = 6.3 ×10^10
The ksp for CuBr = Cu + Br = 6.3 × 10^-9
For the reaction; CuBr +2NH3 = Cu(NH3)2 + Br to calculate K?
K = (6.3 × 10^10)(6.3×10^-9) 
Thus K is 396.9 
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How many moles of oxygen atoms are present in 5 moles of Mg3(PO4)2
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How many grams are in 4.5 x 10^22 molecules of Ba(NO2)2
NNADVOKAT [17]

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17 g Ba(NO₂)₂

General Formulas and Concepts:

<u>Chemistry</u>

  • Stoichiometry
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

<u>Step 1: Define</u>

4.5 × 10²² molecules Ba(NO₂)₂

<u>Step 2: Define conversion</u>

Molar Mass of Ba - 137.33 g/mol

Molar Mass of N - 14.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of Ba(NO₂)₂ - 137.33 + 2(14.01) + 4(16.00) = 229.35 g/mol

<u>Step 3: Dimensional Analysis</u>

<u />4.5 \cdot 10^{22} \ mc \ Ba(NO_2)_2(\frac{1 \ mol \ Ba(NO_2)_2}{6.022 \cdot 10^{23} \ mc \ Ba(NO_2)_2} )(\frac{229.35 \ g \ Ba(NO_2)_2}{1 \ mol \ Ba(NO_2)_2} )

= 17.1384 g Ba(NO₂)₂

<u>Step 4: Check</u>

<em>We are given 2 sig figs. Follow sig fig rules.</em>

17.1384 g Ba(NO₂)₂ ≈ 17 g Ba(NO₂)₂

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