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klasskru [66]
3 years ago
10

Help me..... 25^x=5^x-2

Mathematics
2 answers:
QveST [7]3 years ago
7 0
Ok, under the assumption that the problem is
25^x = 5^{x-2}

as opposed to
25^x = 5^x-2


25^x = 5^{x-2}
looking the the left side

25 = 5^2 so the left side can be written as
(5^2)^x = 5^{x-2}
now, if you remember exponent rules, a power to a power, you just multiply them together
so it would be equal to this equation
5^{2x} = 5^{x-2}

now, since they share the same base (5)
you can jsut compare the exponents

2x= x-2

and then solve for x

trying to solve
25^x = 5^x-2 
requires the use of log i believe

Vikentia [17]3 years ago
4 0
Solve for x right ? . if u find for x . the answer ís x=-2
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