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1 year ago

12

The diameter of a cylindrical container is 22cm. If the volume of the container is 1331cm³, calculate its height.

2 answers:

lisabon 2012 [21]1 year ago

6 0

Answer:

3.5cm

Step-by-step explanation:

Vol=πr²h

Transposing for h,=vol÷πr²

where r=22/2=11cm and taking π=3.142

h=1331/(3.142×(11)²)=3.5cm

garri49 [273]1 year ago

6 0

Answer is 3.5 cm

Step by step

For cylinders we know
Volume = pi x radius ^2 x height

We know volume is 1331
We know pi = 3.14
We know radius is 11 (diameter is 22, so radius is 1/2 of that, so r=11)
We are looking for height “H”

Fill in the numbers into the formula

1331 = 3.14 x 11^2 x H

1331 = 3.14 x 121 x H

1331 = 380 H

Divide both sides by 380 to solve for H

1331/ 380 = 380/ 380 H

3.5 = Height

Problem solved!

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Please help and show work!

sp2606 [1]

Answer:

x=50

Step-by-step explanation:

Because these angles are vertical, they are equal. Let’s find x.

$3x+12=162$

$3x=150$

$x=50$

So, x=50.

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3 years ago

The function f(x) = x2. The graph of g(x) is f(x) translated to the left 6 units and down 5 units. What is the function rule for

Y_Kistochka [10]

Answer:

g(x) = (x + 6)^2 - 5

Step-by-step explanation:

To translate f(x) to the left by 6 units, replace x with x+6.

To translate f(x) down 5 units, replace f(x) with f(x)-5.

Together, these replacements give you ...

... g(x) = f(x+6) -5

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6 0

3 years ago

Write 22 4/5 as a decimal

romanna [79]

change to improper fraction:

22 4/5

22*5=110+4=114

114/5

divide:

114/5=22.8

Thus, 22 4/5 as a decimal is 22.8

7 0

3 years ago

Read 2 more answers

What is the selling price of a $2,499 motorcycle if a $249 discount is given?

erma4kov [3.2K]

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4 years ago

In a certain town, the amount of sulfur oxide in the air, S, in tons, is related to the town’s population, P, in people. The rel

Lady bird [3.3K]

Answer:

Change in sulfur oxide in the air = $\frac{\textup{110010}}{\textup{S}}$

Step-by-step explanation:

Data provided in the question:

Relation between the amount of sulfur oxide in the air and the population as:

S² = 110P² + 20P + 600

Population growth rate, $\frac{\textup{dP}}{\textup{dt}}$ = 10 people per month

Now,

change in sulfur oxide with time i.e $\frac{\textup{dS}}{\textup{dt}}$

differentiating the given relation with respect to time 't'

we have

$2S\frac{\textup{dS}}{\textup{dt}}$ = $2\times110P\frac{\textup{dP}}{\textup{dt}}$ + 20

at P = 100 and $\frac{\textup{dP}}{\textup{dt}}$ = 10 people per month

we have

$2S\frac{\textup{dS}}{\textup{dt}}$ = 2 × 110 × 100 × 10 + 20

or

$2S\frac{\textup{dS}}{\textup{dt}}$ = 220020

or

$\frac{\textup{dS}}{\textup{dt}}$ = $\frac{\textup{220020}}{\textup{2S}}$

or

Change in sulfur oxide in the air = $\frac{\textup{110010}}{\textup{S}}$

8 0

3 years ago