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2 years ago

Evaluate f(t)=-2t^2+ 1 for f(-3). PLEASE HELP I BEG YOU!!!!!!!!!!!

Mathematics

1 answer:

choli [55]2 years ago

6 0

Answer:

$f(-3)=-17$

Step-by-step explanation:

→ Substitute in t = -3 into $f(t)=-2t^{2} +1$

$f(-3)=-2*-3^{2} +1$

→ Simplify

$f(-3)=-2*9 +1$

→ Simplify

$f(-3)=-18 +1$ ⇔ $f(-3)=-17$

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Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.

defon

Answer: 84

<u>Step-by-step explanation:</u>

Set up a proportion as follows: $\dfrac{\text{students that practice everyday}}{\text{total students}}$

$\dfrac{7}{12}=\dfrac{x}{144}$

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2 years ago

Solve the following system of equations using elimination (Do not multipy)

aivan3 [116]

1) 5x - 6y = -32 --> equation 1
3x + 6y = 48 --> equation 2
eliminating y from both of the equations and adding the rest of the terms
we get,
8x = 16
dividing 8 on both sides
x = 2
Substituting the value of x in equation 1
5(2) - 6y = -32
10 - 6y = -32
-6y = -12 ( dividing both sides by -6)
y = 2

2) -3x - 3y = 9 ---> equation 1
3x - 4y = 5 --> equation 2
eliminating x from both equations and adding the rest of the terms
we get,
-7y = 14 ( dividing both sides by -7 )
y = -2
Substituting the value of y in the equation 1
-3x - 3(-2) =9
-3x + 6 = 9 (subtracting both sides by -6)
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Hope this helps you.. :)

5 0

2 years ago

Read 2 more answers

How do I do this. Due tomorrow

kolbaska11 [484]

I prefer D.

It's clear that Kevin took (1/4)x.
Keith took (1/4)x -> kevin's amount
* 2 -> twice.
-1 -> 1 less.

So Kevin + Keith = (1/4)x + (1/4)x * 2 - 1 = (3/4)x - 1.

3 0

3 years ago

Halp me do this pleeeeeasssseee

Sergio039 [100]

Answer:

Step-by-step explanation:

The question isn't clear...

7 0

3 years ago

the vertices of parallelogram abcd are A(4,0,3), B(3,4,-2),C(-2,0,1). find the coodrdinates of fourth vertices

lakkis [162]

Given :

The vertices of parallelogram ABCD are A(4,0,3), B(3,4,-2),C(-2,0,1).

To Find :

The coordinates of fourth vertices.

Solution :

We know, the vertices are ABCD .

Let, point D is (x,y,z) .

Also, diagonals of a parallelogram bisect each other.

Let, point of intersection of daigonal is O.

Coordinates of O are :

$O_x = \dfrac{4+(-2)}{2}= 1\\\\O_y = \dfrac{0+0}{2 } = 0 \\\\O_z = \dfrac{3+1}{2}= 2$

O(1,0,2)

Value of point O through BD.

$O_x = \dfrac{3+x}{2}\\\\x=-1\\\\O_y = \dfrac{4+y}{2}\\\\y = -4\\\\O_z= \dfrac{-2+z}{2}\\\\z = 6$

Therefore, the fourth vertices is D( -1,-4,6 ).

7 0

2 years ago