The two points have the same y value, so it is a horizontal line. Between 5 and 10, the distance is 5.
In fraction form it would be 5/2
Answer:
20sets
Step-by-step explanation:
Since we are to select 3 unordered letters from the word q, u, a, k, e, s, we will apply the combination rule.
For example if r objects are to be selected from n pool of objects, this can be done in nCr number of ways.
nCr = n!/(n-r)!r!
Since the total number of letter in the word q, u, a, k, e, s is 6letters and we are to form 3 letters from it unordered, this can be done in 6C3 number of ways.
6C3 = 6!/(6-3)!3!
6C3 = 6!/3!3!
6C3 = 6×5×4×3×2×1/3×2×1×3×2×1
6C3 = 6×5×4/3×2
6C3 = 120/6
6C3 = 20
Hence 20sets of selection are possible
Answer:
True
Step-by-step explanation:
When sampling is done with replacement, then events are considered to be independent, meaning the result of the first pick will not change the probabilities for the second pick. Without replacement: When sampling is done without replacement, each member of a population may be chosen only once.
It helps to first identify the factors. They are:
- 8
- (x + 4)
- (y + 4)
- (z² + 4z + 7)
Terms are separated by "+" and "-" signs, so that eliminates the first factor, which only has one term. The fourth factor has two "+" signs, and as you can see, it has three terms; that one is out as well. The last two factors both have only one "+" sign, and they both have two terms. Therefore...
Answer:
Two factors in the expression <span>8(x + 4)(y + 4)(z</span>²<span> + 4z + 7) have exactly two terms.</span>
