The rate at which the ice changes is -3/8 lb per hr
<h3>What is the rate the ice changes?</h3>
The given parameters are:
Changes =1 3/4 lb to 1/4 lb
Time = 1/4 hr.
The rate the ice changes is calculated as:
Rate = Change/Time
So, we have
Rate = (1/4 lb - 1 3/4 lb)/(1/4 hr)
Evaluate the difference
Rate = (-1 1/2 lb)/(1/4 hr)
Evaluate the quotient
Rate = -3/8 lb per hr
Hence, the rate at which the ice changes is -3/8 lb per hr
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<span>f(x)=-6x-1
</span><span> X Y
0 -1
-1 5
6 -37
5 -31</span>
Answer:
Search to find the detailed rainfall collections if you want more detailed rainfall intensity data. If all available is monthly average in mm, take the monthly average and divide by number of hours in that month. So if you had 300 mm in April, take 360 mm/(30 days * 24 hours) = 0.5 mm/hour average monthly intensity. so that's it
Answer:
5.83
Step-by-step explanation:
Use the Pythagorean theorem:
3^2+5^2 = c^2
34 = c^2
sqrt34 = c
5.83 = c
Answer:
Dear user,
Answer to your query is provided below
Option (d) is correct.
Step-by-step explanation:
Explanation of the same is attached in image
