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Lady bird [3.3K]
3 years ago
10

Dont need the math just the answers!

Mathematics
2 answers:
marta [7]3 years ago
5 0

Answer:

1.no 2.no 3.no 4.no 5.yes 6.yes

7.yes 8.yes 9.no 10.yes 11. yes 12.yes

Step-by-step explanation:

hope that helps

Mazyrski [523]3 years ago
3 0
Good luck !!!!!!!!!!;$:$:&33
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How do you do this?Can you help me with the steps? I don't really get this a lot
polet [3.4K]
Before you do the steps, change the fractions given to improper fractions:
2 2/3 = 8/3
3 1/6 = 19/6

Now, I think the first step they want you to write is:
8/3 (divided by) 19/6

When you divide two fractions, it's the same as multiplying the first fraction by the reciprocal of the second fraction. (A reciprocal is a fancy way of saying you flip the fraction)
So the next step will look like this:
8/3 x 6/19

With this setup, you can cross simplify the fractions so that they look like this:
8/1 x 2/19
When you multiply this, you get 16/19
Let me know if you have any questions!
4 0
3 years ago
Read 2 more answers
In the triangle, x = 3. Find y.
hoa [83]
Where is this triangle you speak of
6 0
4 years ago
How much is 3×4+9÷6+44×77×777×00+9?​
jarptica [38.1K]

Answer:3*9+9/6+44*77*777*00+9, so using order of applications, it simplifies to 27+1.5+9 after multiplying and dividing, and the final answer is 37.5

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Find the greatest solution for x+y when x^2+y^2 = 7, x^3+y^3=10
damaskus [11]

Answer:

4

Step-by-step explanation:

set

f(x,y)=x+y\\

constrain:

g(x,y)=x^2+y^2 = 7\\h(x,y)=x^3+y^3=10

Partial derivatives:

f_{x}=1\\f_{y} =1 \\g_{x}=2x \\g_{y}=2y\\h_{x}=3x^2 \\h_{y}=3y^2

Lagrange multiplier:

grad(f)=a*grad(g)+b*grad(h)\\

\left[\begin{array}{ccc}1\\1\end{array}\right]=a\left[\begin{array}{ccc}2x\\2y\end{array}\right]+b\left[\begin{array}{ccc}3x^2\\3y^2\end{array}\right]

4 equations:

1=2ax+3bx^2\\1=2ay+3by^2\\x^2+y^2=7\\x^3+y^3=10

By solving:

a=4/9\\b=-2/27\\x+y=4

Second mathod:

Solve for x^2+y^2 = 7, x^3+y^3=10 first:

x=\frac{1}{2} -\frac{\sqrt{13}}{2} \ or \ y=\frac{1}{2} +\frac{\sqrt{13}}{2} \\x=\frac{1}{2} +\frac{\sqrt{13}}{2} \ or \ y=\frac{1}{2} -\frac{\sqrt{13}}{2} \\x+y=-5\ or\ 1 \or\ 4

The maximum is 4

6 0
3 years ago
The table below shows the results of a survey conducted among the employees of a company to find the preferred choices for inves
gladu [14]

Answer: B

Step-by-step explanation:

Took the test

6 0
3 years ago
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