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3 years ago

Find the slope of the line on the graph. Need help please

Mathematics

2 answers:

Natalija [7]3 years ago

5 0

Answer:

The slope is 3

Step-by-step explanation:

The formula for finding slope is change in y over change in x. Also known as rise over run. Go up 3 and go right 1 to get from one point to the next.

Elena-2011 [213]3 years ago

4 0

Answer:

Step-by-step explanation:

Lets consider any 2 points on the line such as (0,2) and (1,5).

The slope of a line = Δy/Δx

Δy = y₂-y₁

Δx = x₂-x₁

y₁=2

y₂=5

x₁=0

x₂= 1

we can now use these values from the two points on the line.

Gradient= (5-2)/(1-0)

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3 years ago

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3 years ago

Circle the equivalent expressions: A. 3(2p + 2) B. 12p C. p(3 + 3) + 6 D. 5p + 6 E. 2p + 4p + 6 F. 3 + 6p + 3

Anuta_ua [19.1K]

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2 years ago

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Fantom [35]

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Step-by-step explanation:

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7 0

3 years ago

Read 2 more answers

If p is a polynomial show that lim x→ap(x)=p(a

Lostsunrise [7]

Let p(x) be a polynomial, and suppose that a is any real number. Prove that

lim x→a p(x) = p(a) .

Solution. Notice that

2(−1)4 − 3(−1)3 − 4(−1)2 − (−1) − 1 = 1 .

So x − (−1) must divide 2x^4 − 3x^3 − 4x^2 − x − 2. Do polynomial long division to get 2x^4 − 3x^3 − 4x^2 – x – 2 / (x − (−1)) = 2x^3 − 5x^2 + x – 2.

Let ε > 0. Set δ = min{ ε/40 , 1}. Let x be a real number such that 0 < |x−(−1)| < δ. Then |x + 1| < ε/40 . Also, |x + 1| < 1, so −2 < x < 0. In particular |x| < 2. So

|2x^3 − 5x^2 + x − 2| ≤ |2x^3 | + | − 5x^2 | + |x| + | − 2|

= 2|x|^3 + 5|x|^2 + |x| + 2

< 2(2)^3 + 5(2)^2 + (2) + 2

= 40

Thus, |2x^4 − 3x^3 − 4x^2 − x − 2| = |x + 1| · |2x^3 − 5x^2 + x − 2| < ε/40 · 40 = ε.

3 0

3 years ago