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3 years ago

What is the area of this figure

Mathematics

2 answers:

lozanna [386]3 years ago

5 0

Answer 190 square inches

Step-by-step explanation:

If there wasn't a piece cut off of the rectangle, you would multiply 22 by 15 because those are the side lengths. However, there is a piece missing so it will not have a great of an area. On the left side, it says that the width is 8 because part of the side is cut off. On the other side, it says 22. This shows that 14 inches is cut off. So width of the missing piece is 14. Then you need to find the length. On the bottom. It says the length is 5 where the top says 15. That shows that 10 inches are missing. That means the missing side is 14x10 which is 140 square inches. If the rectangle was a whole, it would be 330. You subtract 140 from that and it makes 190 square inches.

yaroslaw [1]3 years ago

4 0

Answer:

190 square inches.

Step-by-step explanation:

here is my work to follow to figure out a problem like this.

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mestny [16]

Answer:

x = 18

Step-by-step explanation:

All triangle angles add up to 180 so:

x + 5x + 72 = 180

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6x = 180 - 72

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3 years ago

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a system of equations has infinitely many solutions. if 2y – 4x = 6 is one of the equations, which could be the other equation?

deff fn [24]

<span>A system of equations has infinitely many solutions when the two lines representing the equations coincide. i.e. the two equations are the same or a multiple of each other.
2y - 4x = 6
2y = 4x + 6
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y = 2x + 3
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Hence the other equation is -y = -2x - 3</span>

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3 years ago

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Dahasolnce [82]

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Step-by-step explanation:

4 0

3 years ago

How do I solve for x?

notka56 [123]

Solving:
$\frac{3+4x}{2} + \frac{5-x}{3} = \frac{29}{6}$
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$2,3,6\:|2$
$1,3,3\:|3$
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<span>Replace denominators and resolve:
</span> $\frac{3+4x}{2} + \frac{5-x}{3} = \frac{29}{6}$
$\frac{3(3+4x)}{6} + \frac{2(5-x)}{6} = \frac{29}{6}$
Cancel the dominators
$\frac{3(3+4x)}{\diagup\!\!\!\!6} + \frac{2(5-x)}{\diagup\!\!\!\!6} = \frac{29}{\diagup\!\!\!\!6}$
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$12x - 2x = 29 - 9 - 10$
$10x = 20 - 10$
$10x = 10$
$x = \frac{10}{10}$
$\boxed{\boxed{x = 1}}\end{array}}\qquad\quad\checkmark$

7 0

4 years ago

Let y(????)y(t) be a solution of y˙=17y(1−y7)y˙=17y(1−y7) such that y(0)=14y(0)=14. Determine lim????→[infinity]y(????)limt→[inf

shtirl [24]

Answer:

Step-by-step explanation:

Given that,

y' = 17y ( 1-y^7)

Let y=1

Then, y' = 0 for all t

Then show that it is the only stable equilibrium point so that as y→1, t→∞ with any initial value.

So, the graph solution will be

y(0) = 1 and this will be an horizontal line

If, y(0) > 1 then, y' < 0 by inspecting the first equation, so the graph is has decreasing solution.

Likewise, if y(0) < 1 then, y' > 0 and the graph is increasing.

So no matter the initial condition, graph of the solution will be asymptotic to the horizontal line above.

This make the limit be 1.

This shows that x = 1 is a stable equilibrium.

6 0

3 years ago