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3 years ago

What is the area of this figure

Mathematics

2 answers:

lozanna [386]3 years ago

5 0

Answer 190 square inches

Step-by-step explanation:

If there wasn't a piece cut off of the rectangle, you would multiply 22 by 15 because those are the side lengths. However, there is a piece missing so it will not have a great of an area. On the left side, it says that the width is 8 because part of the side is cut off. On the other side, it says 22. This shows that 14 inches is cut off. So width of the missing piece is 14. Then you need to find the length. On the bottom. It says the length is 5 where the top says 15. That shows that 10 inches are missing. That means the missing side is 14x10 which is 140 square inches. If the rectangle was a whole, it would be 330. You subtract 140 from that and it makes 190 square inches.

yaroslaw [1]3 years ago

4 0

Answer:

190 square inches.

Step-by-step explanation:

here is my work to follow to figure out a problem like this.

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What is the third quartile of this data set? 21,24,25,28,29,35,37,39,42

tangare [24]

Answer:

121.5

Step-by-step explanation:

Find the mean of the last 4 numbers.

8 0

3 years ago

What is the answer to 4-7x=5x

Makovka662 [10]

4-7x=5
+7x +7x
4= 12x
/12 /12

x= 4/12
x= 1/3

3 0

3 years ago

A plane flying horizontally at an altitude of 3 miles and a speed of 500 mi/h passes directly over a radar station. Find the rat

konstantin123 [22]

Answer:

The rate at which the distance from the plane to the station is increasing is 331 miles per hour.

Step-by-step explanation:

We can find the rate at which the distance from the plane to the station is increasing by imaging the formation of a right triangle with the following dimensions:

a: is one side of the triangle = altitude of the plane = 3 miles

b: is the other side of the triangle = the distance traveled by the plane when it is 4 miles away from the station and an altitude of 3 miles

h: is the hypotenuse of the triangle = distance between the plane and the station = 4 miles

First, we need to find b:

$a^{2} + b^{2} = h^{2}$ (1)

$b = \sqrt{h^{2} - a^{2}} = \sqrt{(4 mi)^{2} - (3 mi)^{2}} = \sqrt{7} miles$

Now, to find the rate we need to find the derivative of equation (1) with respect to time:

$\frac{d}{dt}(a^{2}) + \frac{d}{dt}(b^{2}) = \frac{d}{dt}(h^{2})$

$2a\frac{da}{dt} + 2b\frac{db}{dt} = 2h\frac{dh}{dt}$

Since "da/dt" is constant (the altitude of the plane does not change with time), we have:

$0 + 2b\frac{db}{dt} = 2h\frac{dh}{dt}$

And knowing that the plane is moving at a speed of 500 mi/h (db/dt):

$\sqrt{7} mi*500 mi/h = 4 mi*\frac{dh}{dt}$

$\frac{dh}{dt} = \frac{\sqrt{7} mi*500 mi/h}{4 mi} = 331 mi/h$

Therefore, the rate at which the distance from the plane to the station is increasing is 331 miles per hour.

I hope it helps you!

4 0

2 years ago

A man starts at a point A and walks 18 feet north. He then turns and walks due east at 18 feet per second. If a searchlight plac

34kurt

Answer:

1/10 per sec

Step-by-step explanation:

When he's walked x feet in the eastward direction, the angle Θ that the search light makes has tangent

tanΘ = x/18

Taking the derivative with respect to time

sec²Θ dΘ/dt = 1/18 dx/dt.

He's walking at a rate of 18 ft/sec, so dx/dt = 18.

After 3seconds,

Speed = distance/time

18ft/sec =distance/3secs

x = 18 ft/sec (3 sec)

= 54ft. At this moment

tanΘ = 54/18

= 3

sec²Θ = 1 + tan²Θ

1 + 3² = 1+9

= 10

So at this moment

10 dΘ/dt = (1/18ft) 18 ft/sec = 1

10dΘ/dt = 1

dΘ/dt = 1/10 per sec

8 0

3 years ago

4×455 use any strategy to solve?

AnnyKZ [126]

4 x 400 = 1600

4 x 50 = 200

4 = 5 = 20

answer 1820

6 0

3 years ago