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3 years ago

(k+15)-(8+1) when k=10

Mathematics

1 answer:

Ludmilka [50]3 years ago

6 0

=(10+15)-(8+1)
=25-9
=16

The answer is 16

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3 years ago

Write an equation in slope intercept form for the line that passes through (-1, -2) and (3, 4)

LenaWriter [7]

Answer:

The slope-intercept form of the line equation is:

$y=\:\frac{3}{2}x\:-\frac{1}{2}$

Step-by-step explanation:

The slope-intercept form of the line equation

y = mx+b

where

m is the slope

b is the y-intercept

Given the points

(-1, -2)

(3, 4)

Determining the slope between (-1, -2) and (3, 4)

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$\left(x_1,\:y_1\right)=\left(-1,\:-2\right),\:\left(x_2,\:y_2\right)=\left(3,\:4\right)$

$m=\frac{4-\left(-2\right)}{3-\left(-1\right)}$

$m=\frac{3}{2}$

Thus, the slope of the line is:

m = 3/2

substituting m = 3/2 and the point (3, 4) in the slope-intercept form of the line equation

y = mx+b

$4=\frac{3}{2}\left(3\right)+b$

switch sides

$\frac{3}{2}\left(3\right)+b=4$

$\frac{9}{2}+b=4$

subtract 9/2 from both sides

$\frac{9}{2}+b-\frac{9}{2}=4-\frac{9}{2}$

$b=-\frac{1}{2}$

now substituting m = 3/2 and b = -1/2 in the slope-intercept form of the line equation

$y = mx+b$

$y=\:\frac{3}{2}x\:+\:\left(-\frac{1}{2}\right)$

$y=\:\frac{3}{2}x\:-\frac{1}{2}$

Therefore, the slope-intercept form of the line equation is:

$y=\:\frac{3}{2}x\:-\frac{1}{2}$

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