An expression represents the perimeter, in centimeters, of this triangle is 6q + 8r - 5s.
<u>Given the following data:</u>
- b = (5q - 10s) centimeters.
- c = (5s + 7r) centimeters.
<h3>What is a triangle?</h3>
A triangle can be defined as a two-dimensional geometric shape that comprises three (3) sides, three (3) vertices and three (3) angles only.
<h3>How to calculate the perimeter of a triangle?</h3>
Mathematically, the perimeter of a triangle can be calculated by using this formula:
P = a + b + c
<u>Where:</u>
a, b, and c are length of sides.
Substituting the given parameters into the formula, we have;
P = q + r + 5q - 10s + 5s + 7r
P = 6q + 8r - 5s centimeters.
Read more on perimeter of triangle here: brainly.com/question/27109587
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Answer: x = 13
Step-by-step explanation: When solving an equation like this, we are trying to get our variable which is our letter by itself.
So we first want to ask ourselves what is the 14 doing to <em>x</em>. Well, we can see that it's being added to <em>x</em> so to get <em>x</em> by itself, we will do the opposite of addition which is subtraction. So we subtract 14 from both sides of the equation.
The +14 -14 cancels out so we're left with <em>x</em> on the left.
On the right, we must subtract 14 from 27 to get 13.
So we have x = 13 which is the solution to this equation.
Answer:
b-3>15b>18(18 infinity)
Step-by-step explanation:
Answer:
The graph of the function
has a minimum located at (4,-3)
Step-by-step explanation:
we know that
The equation of a vertical parabola in vertex form is equal to

where
a is a coefficient
(h,k) is the vertex of the parabola
If a > 0 the parabola open upward and the vertex is a minimum
If a < 0 the parabola open downward and the vertex is a maximum
In this problem
The coefficient a must be positive, because we need to find a minimum
therefore
Check the option C and the option D
Option C
we have

Convert to vertex form

Factor the leading coefficient





The vertex is the point (4,-3) ( is a minimum)
therefore
The graph of the function
has a minimum located at (4,-3)