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Reil [10]
3 years ago
7

Check all that apply

Mathematics
2 answers:
nlexa [21]3 years ago
8 0

Answer: B & C

Step-by-step explanation:

Putting the values of x & y in all 4 equations we see that the values satisfy equations B & C only. Hence B & C are correct answers

gregori [183]3 years ago
4 0
The answer is B and C
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Drag each interval to a box to show if the function shown is increasing, decreasing, or neither over that interval.
ad-work [718]

Answer:

First, we need to know when the function is increasing, and when is decreasing.

When a function is increasing, it's because to higher <em>x-values </em>belong higher <em>y-values. </em>On the other hand, a function is decreasing when to higher <em>x-values </em>belong lower <em>y-values. </em>The effect in the graph will be a upwards direction of the function when is increasing, and a downwards direction when is decreasing.

So, according to the given graph, we see that between 0 and 4 is increasing, the higher x-values are, higher y-values are. Between 4 and 6 is decreasing, is downwards. Between 6 and 8 is increasing. Between 8 and 10 is decreasing. In finally, between 10 and 14 is neither decreasing or increasing, it remains horizontal.

All these interpretations we can expressed using math language, specifically inequalities:

  • 0 < x < 4: increasing.
  • 4 < x < 6: decreasing.
  • 6 < x < 8: increasing.
  • 8 < x < 10: decreasing.
  • 10 < x < 14: neither increasing or decreasing.

4 0
3 years ago
The population of bacteria in a culture doubles every 14 hours. How long will it take for
Snezhnost [94]

Answer:  22 hours 11 minutes

<u>Step-by-step explanation:</u>

P=P_o\cdot e^{(kt)}\\\\\text{Since the initial population is doubled in 14 hours, then:}\\2P_o=P_o\cdot e^{k\cdot 14}\\2=e^{14k}\\ln\ 2=ln\ e^{14k}\\ln\ 2=14k\\\\\dfrac{ln\ 2}{14}=k\\\\0.0495=k\\\\\\\text{Now that the k-value has been determined, we can find the time when the}\\\text{population is tripled:}\\3P_o=P_o\cdot e^{0.0495t}\\3=e^{0.0495t}\\ln\ 3=ln\ e^{0.0495t}\\ln\ 3=0.0495t\\\\\dfrac{ln\ 3}{0.0495}=5\\\\22.19=t\\\\22\ hrs +0.19\ hrs

22\ hours + \bigg[\dfrac{19}{100}=\dfrac{x}{60}\bigg]\\\\22\ hours + 11\ minutes

4 0
2 years ago
Can someone help me with this question in so confused
Svetlanka [38]

Answer:

D(1, 2) → D'(2, 7)

E(-3, -5) → E'(-10, 0)

F(4, -1) → F'(11, 4)

Step-by-step explanation:

D(1, 2) → D'   ________

Translate image (3x - 1, y + 5)

(1, 2), x = 1 and y = 2

3x - 1 = 3(1) - 1 = 3 - 1 = 2

y + 5 = (2) + 5 = 7

E(-3, -5) → E' ________

(-3, -5), x = -3 and y = -5

3x - 1 = 3(-3) - 1 = -9 - 1 = -10

y + 5 = (-5) + 5 = 0

F(4, -1) → F'   ________

(4, -1), x = 4 and y = -1

3x - 1 = 3(4) - 1 = 12 - 1 = 11

y + 5 = (-1) + 5 = 4

3 0
1 year ago
Find the equation of a line that is parallel to y = 2x + 3 and passes through (-1, -1).
drek231 [11]

Answer:

  y = 2x +1

Step-by-step explanation:

The given line is in "slope-intercept" form, where the slope is the coefficient of x, 2, and the intercept is the added constant, 3. The parallel line will have the same slope, but its constant will be different. We can find the constant by putting the given point into an equation with the constant as the unknown:

  y = 2x + b

  -1 = 2(-1) +b . . . substitute for x and y

 2 -1 = b . . . . . . add 2

  1 = b

So the equation for the parallel line is ...

  y = 2x + 1

4 0
3 years ago
How to find MP when discount percent and SP are given​
nadezda [96]

Given:

Consider the discount percent and SP are given​.

To find:

The MP.

Solution:

Let x% be the discount percent Then

SP=MP-x\%\text{ of }MP

SP=MP-\dfrac{x}{100}MP

SP=\left(1-\dfrac{x}{100}\right)MP

SP=\left(\dfrac{100-x}{100}\right)MP

Multiply both sides by 100.

100SP=(100-x)MP

Divide both sides by (100-x).

\dfrac{100}{100-x}SP=MP

Therefore, the formula for MP is MP=\dfrac{100}{100-x}SP, where x is the discount percentage.

7 0
2 years ago
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