Answer:
Solution given:
Volume of cuboid=975cm³
length[l]=15cm
width[w]=130mm=13cm
height [h]=?
we have:
Volume of cuboid=l*w*h
975=15*13*h
h=
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Log₄8 + 3 · log₄x
so the easiest way to do this is to note that these logs are separated by an addition symbol--it isn't "log₄8 + 3" times "log₄x"
log₄8
plus
3 · log₄x
for the second log, you can condense it with log properties/rules: the coefficient out front, when you condense it, becomes the exponent for the argument of your log:
3 · log₄x = log₄(x³)
so, having condensed that, your equation reads:
log₄8 + log₄(x³)
you could technically evaluate the first log, but the question wants both of these to become a single logarithm, which means you want to combine them. log properties state that if logs are being added, you can multiply their arguments (for example: logₓab = logₓa + logₓb)
you just want to apply that property to this, so you'll be multiplying your arguments 8 and x³:
log₄(8x³) is the answer, expressed as one logarithm.
Answer:
334
Step-by-step explanation:
<h3>2000 items cost $ 7500</h3>
<em><u>Solution:</u></em>
Given that,
The function is:
C(x) = 1500 + 3x
Where,
C(x) is the total cost
"x" is the number of manufactured items
<em><u>How much would 2,000 items cost</u></em>
Substitute x = 2000 in given function
C(2000) = 1500 + 3(2000)
C(2000) = 1500 + 6000
C(2000) = 7500
Thus 2000 items cost $ 7500