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satela [25.4K]
3 years ago
12

If f(x) = x2 − 1, and f(2a) = 35, then what could be the value of a ?

Mathematics
1 answer:
SVEN [57.7K]3 years ago
4 0
F(2a)=35
35=(2a)^2-1
35=4a^2-1
minus 35 from both sidse
0=4a^2-36
facor out 4
0=4(a^2-9)
factor differece of 2 perfect squares
0=4(a-3)(a+3)
set to zero
a-3=0
a=3

a+3=0
a=-3


a=-3 or 3
hope that's what you're looking for.
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For i≥1 , let Xi∼G1/2 be distributed Geometrically with parameter 1/2 . Define Yn=1n−−√∑i=1n(Xi−2) Approximate P(−1≤Yn≤2) with l
murzikaleks [220]

Answer:

The answer is "0.68".

Step-by-step explanation:

Given value:

X_i \sim \frac{G_1}{2}

E(X_i)=2 \\

Var (X_i)= \frac{1- \frac{1}{2}}{(\frac{1}{2})^2}\\

             = \frac{ \frac{2-1}{2}}{\frac{1}{4}}\\\\= \frac{ \frac{1}{2}}{\frac{1}{4}}\\\\= \frac{1}{2} \times \frac{4}{1}\\\\= \frac{4}{2}\\\\=2

Now we calculate the \bar X \sim N(2, \sqrt{\frac{2}{n}})\\

\to \frac{\bar X - 2}{\sqrt{\frac{2}{n}}}  \sim  N(0, 1)\\

\to \sum^n_{i=1}  \frac{X_i - 2}{n}  \times\sqrt{\frac{n}{2}}}  \sim  N(0, 1)\\\\\to  \sum^n_{i=1}  \frac{X_i - 2}{\sqrt{2n}}  \sim  N(0, 1)\\

\to Z_n = \frac{1}{\sqrt{n}} \sum^n_{i=1} (X_i -2) \sim N(0, 2)\\

\to P(-1 \leq X_n \leq 2)  = P(Z_n \leq Z) -P(Z_n \leq -1) \\\\

                               = 0.92 -0.24\\\\= 0.68

6 0
3 years ago
Imagine that you are given two linear equations in slope-intercept form. You notice that the slopes are the same, but the y-inte
Hitman42 [59]

B

If two lines have the same slope and different intercepts, then they will never cross each other; they are parallel lines. Therefore, they have no solutions since a solution is where the lines cross.

7 0
3 years ago
Write the product in standard form: (x+4)(x-4)
Genrish500 [490]

Answer:

x² - 16

Step-by-step explanation:

Use the FOIL method here where

F = first

O = outer

I = inner

L = last

F = x * x = x²

O = -4 * x = -4x

I = 4 * x = 4x

L = -4 * 4 = -16

Combine the terms to get x² - 16.

8 0
3 years ago
The rent for an apartment was $6,600 per year in 2012. If the rent increased at a rate of 4% each year thereafter, use an expone
Serhud [2]

Answer:

$9,393.78

Step-by-step explanation:

Using the equation:

A = P(1+r)^t

Where,

A = final amount

P = initial amount = $6,600

r = rate of increase = 4% = 0.04

t = time in years = 9 years (2012-2021)

A = 6,600(1 + 0.04)^9

= 6,600(1.04)^9

= 6,600(1.4233)

= 9,393.78

A = $9,393.78

7 0
3 years ago
Evaluate:<br> (a)<br> (8 x 8) - 24
Alexus [3.1K]

Answer:

40

Step-by-step explanation:

i solved for you

hope it helped! ;)

6 0
3 years ago
Read 2 more answers
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