2 years ago

Determine the interquartile range for the given data 11, 13, 16, 17, 8, 10, 14, 14, 17, 14

Mathematics

1 answer:

Elanso [62]2 years ago

7 0

Answer:

<em>(IQR) interquartile range: 4.5!</em>

Step-by-step explanation:

8, 10, 11, 13, 14, 14, 14, 16, 17

Median: 14

Lower quartile: 10.5

Upper quartile: 15

Interquartile range: 15 - 10.5 = 4.5

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Here we are given the three sides of the triangle.

So we have Heron's formula to find its area.

Heron's formula is given by :

$A= \sqrt{S(S-A)(S-B)(S-C)}$

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$S= \frac{A+B+C}{2}$

plugging values of A, B and C to find S

$S= \frac{9+6+12}{2}$

S=13.5

Now plugging values of A, B , C and S in Heron's formula

$A= \sqrt{13.5(13.5-9)(13.5-6)(13.5-12)}$

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