Answer: a) 0.0792 b) 0.264
Step-by-step explanation:
Let Event D = Families own a dog .
Event C = families own a cat .
Given : Probability that families own a dog : P(D)=0.36
Probability that families own a dog also own a cat : P(C|D)=0.22
Probability that families own a cat : P(C)= 0.30
a) Formula to find conditional probability :
(1)
Similarly ,

Hence, the probability that a randomly selected family owns both a dog and a cat : 0.0792
b) Again, using (2)

Hence, the conditional probability that a randomly selected family owns a dog given that it owns a cat = 0.264
Answer:
Gain = S.P - C.P
Loss =C.P - S.P
where, S.P equals spelling price
and C.P equals cost price
Step-by-step explanation:
Hope it helps
Answer:
Step-by-step explanation:
i can help
Step 1
4( − 11) = 15 − 4 Solving
Step 2
4( − 11) = 15 − 4 Simplify
15-4
-44=11
Answer
Unique solution
Hope this helps
-4x+y= -9 can be turned into
y= -9 + 4x
5x+2y=3 (plug y in)
5x+2(-9+4x)=3
5x-18+8x=3
5x+8x=3+18
13x=21
divide 13 on both sides
x=1.6