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gtnhenbr [62]
3 years ago
8

Which is the value of x? X=16 X=29 X=44 X=46

Mathematics
2 answers:
Dahasolnce [82]3 years ago
5 0

Answer:

x = 16

I hope this helps!

Elis [28]3 years ago
5 0

Answer:

x=16

Step-by-step explanation:

The angles of the inside of a triangle always add up to 180

2*16= 32

3*16=48

16+84=100

32+48+100=180

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PLSSSS HELP<br><br> Find the intersection of the circle x^2+ y^2 = 29 and y = x - 3 algebraically,
Marina86 [1]
Uhhh what grade u in?!?
6 0
3 years ago
A globe of the moon has a radius of 10 inches. Find the volume of the globe. Round your answer to the nearest whole number.
Mariulka [41]
It would be 4,189 m3
4 0
3 years ago
Find all of the eigenvalues λ of the matrix A. (Hint: Use the method of Example 4.5 of finding the solutions to the equation 0 =
Svetradugi [14.3K]

Answer:

\lambda=8,\ \lambda=-5

Step-by-step explanation:

<u>Eigenvalues of a Matrix</u>

Given a matrix A, the eigenvalues of A, called \lambda are scalars who comply with the relation:

det(A-\lambda I)=0

Where I is the identity matrix

I=\left[\begin{array}{cc}1&0\\0&1\end{array}\right]

The matrix is given as

A=\left[\begin{array}{cc}3&5\\8&0\end{array}\right]

Set up the equation to solve

det\left(\left[\begin{array}{cc}3&5\\8&0\end{array}\right]-\left[\begin{array}{cc}\lambda&0\\0&\lambda \end{array}\right]\right)=0

Expanding the determinant

det\left(\left[\begin{array}{cc}3-\lambda&5\\8&-\lambda\end{array}\right]\right)=0

(3-\lambda)(-\lambda)-40=0

Operating Rearranging

\lambda^2-3\lambda-40=0

Factoring

(\lambda-8)(\lambda+5)=0

Solving, we have the eigenvalues

\boxed{\lambda=8,\ \lambda=-5}

8 0
3 years ago
The seasonal output of a new experimental strain of pepper plants was carefully weighed. The mean weight per plant is 15.0 pound
DanielleElmas [232]

Answer:

There are 118 plants that weight between 13 and 16 pounds

Step-by-step explanation:

For any normal random variable X with mean μ and standard deviation σ : X ~ Normal(μ, σ)  

This can be translated into standard normal units by :  

Z = \frac{(X - \mu)}{\sigma}

Let X be the weight of the plant  

X ~ Normal( 15 , 1.75 )  

To find : P( 13 < X < 16 )  

= P(\frac{( 13 - 15 )}{1.75} < Z < \frac{( 16 - 15 )}{1.75})

= P( -1.142857 < Z < 0.5714286 )  

= P( Z < 0.5714286 ) - P( Z < -1.142857 )  

= 0.7161454 - 0.1265490  

= 0.5895965  

So, the probability that any one of the plants weights between 13 and 16 pounds is 0.5895965  

Hence, The expected number of plants out of 200 that will weight between 13 and 16 = 0.5895965 × 200

                                            = 117.9193  

Therefore, There are 118 plants that weight between 13 and 16 pounds.

4 0
3 years ago
Volume of a rectangular Pyramid that has a height of 9 cm length of 8 cm and a width of 9 cm
Alexus [3.1K]

Answer:

length = 8 cm

breadth = 9 cm

height = 9cm

Volume = ?

now,

Volume = l×b×h

= 8cm ×9cm ×9cm

= 648 cm^3.

5 0
3 years ago
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