Answer:
0.1507 or 15.07%.
Step-by-step explanation:
We have been given that the manufacturing of a ball bearing is normally distributed with a mean diameter of 22 millimeters and a standard deviation of .016 millimeters. To be acceptable the diameter needs to be between 21.97 and 22.03 millimeters.
First of all, we will find z-scores for data points using z-score formula.
, where,
z = z-score,
x = Sample score,
= Mean,
= Standard deviation.



Let us find z-score of data point 22.03.



Using probability formula
, we will get:

Therefore, the probability that a randomly selected ball bearing will be acceptable is 0.1507 or 15.07%.
Answer:
(A) 0.006593 or 0.6593%
(B) 0.01538 or 1.538%
Step-by-step explanation:
The total number of possibilities to pick 3 parts out of 15 possible parts is given by the following combination:

(A) There are only three possibilities for which the inspector finds exactly one nonconforming part (NCC, CNC, CCN). Therefore, the probability is:

(B) There are three possibilities for which the inspector finds exactly one nonconforming part, three possibilities for two nonconforming parts (NNC, CNN, NCN), and one possibility for all nonconforming parts (NNN). The probability that the inspector finds at least one nonconforming part is:

Answer:
x=0.933333
Step-by-step explanation:
First you add 6 to both sides of the equation
15x - 6 + 6 = 8 +6
That gives you 15x = 14
Then you divide 15 on both sides of the equation
That gives you x = 14/15 = 0.93333