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Alinara [238K]
2 years ago
7

This is from Khan academy I have to attach a PNG if you can help me solve it! Thank you!

Mathematics
1 answer:
Mekhanik [1.2K]2 years ago
7 0

49^2m-m : Not equivalent

7^2m-2m : Not equivalent

7^2m-m : Not equivalent

This is actually a trick question. All of the following are actually false statements. Want to know why? Let me show you.

For exponents, if you are dividing a number to some power (i.e 5^3) by the SAME number to a different power (i.e 5^2), then the expression is 5^3-2 or 5^1 = 5. This is true for any number a such that a^b ÷ a^c = a^b-c.

Since 7 and 49 are not the same number, this rule does not apply and thus cannot be simplified any further.

Let me prove why. 5^3 = 125, and 5^2 = 25, and 125 ÷ 25 = 5. This is also the same as 5^3-2 = 5^1 = 5. We just proved this as so.

But, what about 7 and 49, or 2 different numbers. Well it doesn't apply. 7^3 = 343, and 49^2 = 2401, and 343 ÷ 2401 ≈ 0.14. Thus, this is NOT equal to 7^3-2 which is 7. We just proved that a^y ÷ b^z ≠ a^y-z. Congratulations!

Hope this helped!

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Answer:

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If f(x) and f^-4(x) are inverse functions of each other and f(x) = 2x+5, what is f^-1(x)?
miss Akunina [59]

For this case we must find the inverse of the following function:

f (x) = 2x + 5

Then, we follow the steps:

We change f (x)by y:

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Answer:

A) 2x³+11x²+8x-16

Step-by-step explanation:

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