Answer:
C. Test for Goodness-of-fit.
Step-by-step explanation:
C. Test for Goodness-of-fit would be most appropriate for the given situation.
A. Test Of Homogeneity.
The value of q is large when the sample variances differ greatly and is zero when all variances are zero . Sample variances do not differ greatly in the given question.
B. Test for Independence.
The chi square is used to test the hypothesis about the independence of two variables each of which is classified into number of attributes. They are not classified into attributes.
C. Test for Goodness-of-fit.
The chi square test is applicable when the cell probabilities depend upon unknown parameters provided that the unknown parameters are replaced with their estimates and provided that one degree of freedom is deducted for each parameter estimated.
First problem:
n/4 + 2 = -9
-2 -2
n/4 = -11
x4 x4
n = -44
Check:
-44/4 + 2 = -9
-11 + 2 = -9
-9 = -9
Second problem:
3/4x = -12
0.75x = -12
-------- ----
0.75 0.75
x = -16
3/4 * (-16) = -12 OR 0.75 * (-16) = -12
-12 = -12
Still get the same answer.
Answer:
Do you have the a picture of the table
Answer:
The statement represents the IDENTITY PROPERTY OF ADDITION.
Step-by-step explanation:
Here, the given expression is 8 + 0 = 8
IDENTITY ELEMENT : Identity element is a special type of element in a given set of system, such that any number remains UNALTERED if operated with the identity element.
⇒ a + X = X for, a ≡ IDENTITY ELEMENT
Now, 8 + 0 = 8
Comparing it with the above equation , we get
0 ≡ IDENTITY ELEMENT in the given Binary operation of Addition.
Hence, the statement represent the IDENTITY PROPERTY OF ADDITION.
Answer:
cannot be used to prove or disprove a conjecture