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valkas [14]
2 years ago
6

How to simplify mixed fraction like 6 15/9

Mathematics
2 answers:
Alex2 years ago
6 0
Multiply 6 by 9 (whole number by denominator)
then add that to 15 (the product to the numerator.
GarryVolchara [31]2 years ago
3 0
The answer is 7.6666
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Find the equation of the line that passes through the given points. (1, 4.5) and (3, 6)
Zanzabum

Answer:

y=0.75x+3.75

Step-by-step explanation:

The slope is

\frac{6 - 4.5}{3 - 1}  =   \frac{3}{4}

Substituting into point-slope form,

y - 6 = 0.75(x - 3)

y - 6 = 0.75x - 2.25

y = 0.75x + 3.75

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Which type of graph would be best for showing the average yearly bonus amounts for employees in different departments of an IT c
nika2105 [10]
I believe it is C. a histogram
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5 0
3 years ago
Solve the system by graphing. It is REQUIRED to check your solution. Show work for this problem on your work page.
Hunter-Best [27]

Answer:

y=x-1

y=-2x-4

although I cant summon a graph for this one, I can give cords

for first graph (-2,-3),(-1,-2),(0,-1), (1,0),(2,1)

For second graph the slope is down 2 over 1, and begins at (0,-4).

(-2,0)(-1,-2),(0,-4),(1,-6),(2,-8)

6 0
2 years ago
Read 2 more answers
There are 15 identical pens in your drawer, nine of which have never been used. On Monday, yourandomly choose 3 pens to take wit
DaniilM [7]

Answer: p = 0.9337

Step-by-step explanation: from the question, we have that

total number of pen (n)= 15

number of pen that has never been used=9

number of pen that has been used = 15 - 9 =6

number of pen choosing on monday = 3

total number of pen choosing on tuesday=3

note that the total number of pen is constant (15) since he returned the pen back .

probability of picking a pen that has never been used on tuesday = 9/15 = 3/5

probability of not picking a pen that has never been used on tuesday = 1-3/5=2/5

probability of picking a pen that has been used on tuesday = 6/15 = 2/5

probability of not picking a pen that has not been used on tuesday= 1- 2/5= 3/5

on tuesday, 3 balls were chosen at random and we need to calculate the probability that none of them has never been used .

we know that

probability of ball that none of the 3 pen has never being used on tuesday = 1 - probability that 3 of the pens has been used on tuesday.

to calculate the probability that 3 of the pen has been used on tuesday, we use the binomial probability distribution

p(x=r) = nCr * p^{r} * q^{n-r}

n= total number of pens=15

r = number of pen chosen on tuesday = 3

p = probability of picking a pen that has never been used on tuesday = 9/15 = 3/5

q = probability of not picking a pen that has never been used on tuesday = 1-3/5=2/5

by slotting in the parameters, we have that

p(x=3) = 15C3 * (\frac{2}{5})^{3} * (\frac{3}{5})^{12}

p(x=3) = 455 * 0.4^{3} * 0.6^{12}

p(x=3) = 455 * 0.064 * 0.002176

p(x=3) = 0.0633

thus probability that 3 of the pens has been used on tuesday. = 0.0633

probability of ball that none of the 3 pen has never being used on tuesday  = 1 - 0.0633 = 0.9337

3 0
2 years ago
Blank3-2Blank=71...what is the answer? Answer please
ollegr [7]
I think it’s 60 if that’s what your asking
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2 years ago
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