Someone has 240$ for a road trip this is 2/5of the coast of the trip how much dose the trip coat

saw5 [17]

Answer:

<h2>Solution: Since, the prime factors of 226 are 2, 113. Therefore, the product of prime factors = 2 × 113 = 226.</h2>

Step-by-step explanation:

<h2>(｡♡‿♡｡)______________________</h2><h2>PLEASE MARK ME BRAINLIEST AND FOLLOW M E AND SOUL DARLING TEJASWINI SINHA HERE ❤️</h2>

4 0

2 years ago

Read 2 more answers

A leaky faucet in kali's house drips water at a rate of 42 gallons per week. How many gallons does the faucet drip in three days

Ratling [72]

Amount of water that the faucet leaks in 1 week = 42 gallons

That means Amount of water that the faucet in Kali's house leaks in 7 days = 42 gallons So The amount of water that the faucet in Kali's house leaks in 1 day = (42/7) gallons = 6 gallons Then The amount of water that the faucet in Kali's house leaks in 3 days = 6 * 3 gallons = 18 gallons

So it can said from the above deduction that the amount of water leaked by the faucet in Kali's house is 18 gallons.

hope this help .-.

5 0

2 years ago

A community is planning to build a rectangular garden.the width of the garden is 27/4 feet and the perimeter of the garden is 37

Crank

We know that the width of the garden is = $\frac{27}{4}$ feet = 6.75 feet

and Perimeter of the garden is = 37.5 feet

Also, we know that for a rectangular space perimeter = 2 * (l + w)

⇒ 37.5 = 2 * (l + 6.75)

⇒ 37.5 = 13.5 + 2*l

⇒ 24 = 2*l

⇒ l = 12 feet

Now, we need to determine how much square feet of mulch is required, hence we need to calculate the area of the garden

Area = l * w

⇒ Area = 12 * 6.75

⇒ Area = 81 square feet

Hence, they require 81 square feet of mulch

7 0

3 years ago

We want to find the zeros of this polynomial:

fredd [130]

Answer:

x = -3 and x = -3/2

Step-by-step explanation:

After writing down the polynomial, split it; put a line between 3x^2 and -18x. Look and 2x^3 + 3x^2 and -18x - 27 separately and factor them both:

p(x) = 2x^3 + 3x^2 - 18x -27

p(x) = x^2(2x+3) -9(2x+3)

Now notice how x^2 and -9 have the same factor (2x+3). That means x^2 and -9 can go together:

p(x) = (x^2 - 9)(2x+3)

Factor it once more because there's a difference of squares:

p(x) = (x+3)(x-3)(2x+3)

Now just plug in whatever makes the each bracket equal 0:

x = -3, x = 3, and x = -3/2

Those are your zeros.

8 0

2 years ago

Adding and subtracting the given polynomials

Usimov [2.4K]

You have to combine like terms, so the variable (x, y, s, d, c....) and the exponents must be the same in order to combine them.

For example:

x² + x³ Since they don't have the same exponent, you can't combine them

y² + 3y² = 4y²

23x + x = 24x

4. 2s² + 1 + s² - 2s + 1 You can rearrange it if it makes it easier

2s² + s² - 2s + 1 + 1 = 3s² - 2s + 2

5. 5t² - 2t - 1 - (3t² - 5t + 7) Distribute/multiply the - to (3t² - 5t + 7)

5t² - 2t - 1 - 3t² + 5t - 7 = 2t² + 3t - 8

Do the same for #9 and #10, and you should get:

9. 2k² + 5k - 9

10. 6y³ - 7y² - 6y - 12

3 0

2 years ago