I believe it's four times as great : )
Answer:
Step-by-step explanation:
we know that
A line parallel to the x-axis is a horizontal line
The equation of a horizontal line is equal to the y-coordinate of the point that passes through it
In this problem the line passes through the point (6,-6)
so
The y-coordinate is -6
therefore
The equation of the line is
Answer:
Hey there!
6 is an integer, whole number, and real number.
Let me know if this helps :)
A. that is b^2-4ac
for
ax^2+bx+c
the deterimant (part under the radicand)
is b^2-4ac
if it is
1. less than 0 then there are no real solutions
2. eqal to 0 then there is 1 real solution
3. greater than 0, there are 2 real roots
9x^2-16x+60
b^2-4ac=(-16)^2-4*9*60=256-2160<0
no real solutions
B. grouping
ac method
4 times -5=-20
what 2 numbers multiply to get -20 and add to get 8?
-2 and 10
seperate the middle number to get that
4x^2-2x+10x-5=0
(4x^2-2x)+(10x-5)=0
2x(2x-1)+2(2x-1)=0
(2x-1)(2x+2)=0
set equal to 0
2x-1=0
2x=1
x=1/2
2x+2=0
2x=-2
x=-1
x=1/2 or -1
Answer:
What?
Step-by-step explanation:
is this your whole question?
