<span>1) We are given that PA = PB, so PA ≅ PB by the definition of the radius.
</span>When you draw a perpendicular to a segment AB, you take the compass, point it at A and draw an arc of size AB, then you do the same pointing the compass on B. Point P will be one of the intersections of those two arcs. Therefore PA and PB correspond to the radii of the arcs, which were taken both equal to AB, therefore they are congruent.
2) We know that angles PCA and PCB are right angles by the definition of perpendicular.
Perpendicularity is the relation between two lines that meet at a right angle. Since we know that PC is perpendicular to AB by construction, ∠PCA and ∠PCB are right angles.
3) PC ≅ PC by the reflexive property congruence.
The reflexive property congruence states that any shape is congruent to itself.
4) So, triangle ACP is congruent to triangle BCP by HL, and AC ≅ BC by CPCTC (corresponding parts of congruent triangles are congruent).
CPCTC states that if two triangles are congruent, then all of the corresponding sides and angles are congruent. Since ΔACP ≡ ΔBCP, then the corresponding sides AC and BC are congruent.
5) Since PC is perpendicular to and bisects AB, P is on the perpendicular bisector of AB by the definition of the perpendicular bisector.
<span>The perpendicular bisector of a segment is a line that cuts the segment into two equal parts (bisector) and that forms with the segment a right angle (perpendicular). Any point on the perpendicular bisector has the same distance from the segment's extremities. PC has exactly the characteristics of a perpendicular bisector of AB. </span>
Interpreting the inequality, it is found that the correct option is given by F.
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- The first equation is of the line.
- The equal sign is present in the inequality, which means that the line is not dashed, which removes option G.
In standard form, the equation of the line is:
Thus it is a decreasing line, which removes options J.
- We are interested in the region on the plane below the line, that is, less than the line, which removes option H.
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- As for the second equation, the normalized equation is:
- Thus, a circle centered at the origin and with radius 2.
- Now, we have to check if the line
, with coefficients 
, intersects the circle, of centre 
- First, we find the following distance:
- Considering the coefficients of the line and the center of the circle.
- This distance is less than the radius, thus, the line intersects the circle, which removes option K, and states that the correct option is given by F.
A similar problem is given at brainly.com/question/16505684
Answer:
y=-13x + 78 I'm not sure what's up with those answer choices though
Answer:
30
Step-by-step explanation:
x+50=180(संगत कोन भएकाले )
x=180-50
X=130
अब,
130-100=30
