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Brut [27]
3 years ago
12

We learned that division expressions that have the same quotient and remainder are not necessarily equal to each other explain h

ow this is possible
Mathematics
2 answers:
Misha Larkins [42]3 years ago
7 0

Division expressions that have the same quotient and remainder are not necessarily equal to each other. This is possible because each expressions have different numbers so the calculation can be different

<h3>Further explanation </h3>

Division is breaking the number up into the equal number of parts.

We learned that division expressions that have the same quotient and remainder are not necessarily equal to each other. For example when we get 20 divided by 4 then If we take 20 things and put them into four equal sized groups, there will be 5 things in each group. Therefore the answer is 5 and hence it will not be any remainder (remainder is 0).

Another example is when we get 21 divided by 4 then If we take 21 things and put them into four equal sized groups, there will be 5 things in each group and the remainder of 1.

Third example is when we get 26 divided by 5 then If we take 26 things and put them into four equal sized groups, there will be 5 things in each group and the remainder of 1.

Division expressions that have the same quotient and remainder are not necessarily equal to each other. This is possible because each expressions have different numbers so the calculation can be different. The difference is that the remainders are not the same in every expressions.  The first remainder is 1 part out of 4, when the third remainder is 1 part out of 5.

<h3>Learn more</h3>
  1. Learn more about division brainly.com/question/471768
  2. Learn more about quotient brainly.com/question/8921605
  3. Learn more   about remainder brainly.com/question/5423

<h3>Answer details</h3>

Grade:    5

Subject:  Math

Chapter:  expressions

Keywords:  division, quotient, remainder, expressions, equal

olasank [31]3 years ago
6 0
<span>Let's say you divide 25 by 4.  You will get a quotient 6, but have that remainder of 1.  You could also divide 37 by 6, and likewise get a quotient of 6, with a remainder of 1.  The difference is that the remainders are not truly the same.  The first remainder is 1 part out of 4, but the second remainder is 1 part out of 6</span>
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Measure the screwdriver's length to the nearest tenth of a centimeter. Express the answer as a decimal.
Alja [10]

Answer:

17.1 cm

Step-by-step explanation:

A screw driver is a mechanical tool or device which is mainly used for screwing the screws and unscrewing them. It is also used for removing the nuts and bolts and also serves a variety of uses.

It is typically made of steel and has a handle and a shaft which ends as a tip.

In the context, the length of the screw driver from the given figure expressed to the nearest tenth of a centimeter is 17.1 cm.

It is also equivalent to $6\frac{3}{4}$ inch.

8 0
3 years ago
Let P be a point between points S and T on 2004-01-01-02-00_files/i0120000.jpg. If ST = 21, SP = 3b – 11, and PT = b + 4, solve
NNADVOKAT [17]
The best and most correct answer among the choices provided by your question is the third choice or letter C.

<span>If ST = 21, SP = 3b – 11, and PT = b + 4, the value of b would be 14.

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I hope my answer has come to your help. God bless and have a nice day ahead!
7 0
3 years ago
Read 2 more answers
A cylinder has a volume of 384 cubic inches and a height of 8 inches, what is the radius
Triss [41]
The answer is:  3.91 inches .
___________________________________________

Note:  Volume of cylinder: V = (base area) * (height);

in which: V = volume = 384 in.³ ;
              h = height = 8 in. ; 
              Base area = area of the base (that is; "circle") = π r² ;
                                         in which; "r" = radius; 
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Solve for "r" :
___________________________________________
 V = π r² * (8 in.) ; 

384 in.³ = (8 in.) * (π r²) ;
___________________________________________
Divide EACH SIDE of the equation by "8" ; 
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 (384 in.³) / 8 = [ (8 in.) * (π r²) in.] / 8 ; 
___________________________________________
 to get: 
___________________________________________
   48 in.³ = (π r²) in.² * in.   ;
___________________________________________
 ↔  (π r²) in.² * in. =  48 in.³  ;  
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Rewrite this equation; using "3.14" as an approximation for: π ;
__________________________________________________
 (3.14 * r²) in.² * in. =  48 in.³ 
_______________________________________
Divide EACH SIDE of the equation by:

"[(3.14)*(in.²)*(in.)]" ;  to isolate "r² " on one side of the equation; 
                                 (since we want to solve for "r") ;
_____________________________________________________
→ [(3.14 * r²) in.² * in.] / [(3.14)*(in.²)*(in.)]  = 48 in.³ / [(3.14)*(in.²)*(in.)] ; 
__________________________________________________
→ to get:   r² = 48/3.14 ;
________________________
      → r² = 15.2866242038216561 ;
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To solve for "r" (the radius; take the "positive square root" of EACH side of the equation:
__________________________________________________
     → +√(r²) = +√(15.2866242038216561)
__________________________________________________
     →  r = 3.9098112747064475286  ; round to 3.91 inches .
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4 0
3 years ago
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The conditional relative frequency table was generated using data that compares the number of voters in the last election and wh
lidiya [134]

Using proportions, it is found that 66 people in the survey worked on election day.

<h3>What is a proportion?</h3>

A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct or inverse proportional, can be built to find the desired measures in the problem.

For this problem, the amounts of people who worked are:

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Hence the total amount is given by:

0.64 x 50 + 0.4 x 85 = 66.

66 people in the survey worked on election day.

More can be learned about proportions at brainly.com/question/24372153

#SPJ1

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2 years ago
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Alex777 [14]

Answer:

<h2>Real zeros: x = 2</h2><h2>All zeros: x = 2, x = -4i and x = 4i</h2>

Step-by-step explanation:

f(x)=x^3-2x^2+16x-32\\\\\text{The zeros:}\\\\f(x)=0\Rightarrow x^3-2x^2+16x-32=0\\\\x^2(x-2)+16(x-2)=0\\\\(x-2)(x^2+16)=0\iff x-2=0\ \vee\ x^2+16=0\\\\x-2=0\qquad\text{add 2 to both sides}\\\boxed{x=2}\\\\x^2+16=0\qquad\text{subtract 16 from both sides}\\x^2=-16

8 0
3 years ago
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