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Vilka [71]
3 years ago
7

Which quantum number gives the approximate energy of an electron in the quantum mechanical model of the atom? A) n B) I C) m1 D

) m2 E) none of the above.
Physics
1 answer:
alexdok [17]3 years ago
4 0

Answer:

Option A) n

Explanation:

In accordance to Quantum Mechanical model of an atom:

  • The Principle Quantum number (n) gives the description of the shell of an electron and the energy level of an electron in an atom.
  • The angular momentum also referred to as Azimuthal Quantum number (l) gives the description of  the shape of the orbitals and helps in determination of angular momentum magnitude.
  • The magnetic quantum number (m_{1}) describes the energy levels or the number of orbitals contained in a subshell and the way these are oriented within.
  • The spin quantum no. (m_{2}) determines the elelctron spin's direction which may be (-\frac{1}{2}) or (+\frac{1}{2}).
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Answer:

<u>Assuming b = 9.3i + 9.5j</u> <em>(b = 931 + 9.5 is wrong):</em>

a) a×b = 34.27k

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d) The component of a along the direction of b = 9.66

Explanation:

<u>Assuming b = 9.3i + 9.5j</u> <em>(b = 931 + 9.5 is wrong)</em> we can proceed as follows:  

a) The vectorial product, a×b  is:

a \times b = (8.6*9.5 - 5.1*9.3)k = 34.27k

b) The escalar product a·b is:

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c) <u>Asumming (a</u><u> </u><u>+ b)·b</u> <em>instead a+b·b</em> we have:

(a + b)\cdot b = [(8.6 + 9.3)i + (5.1 + 9.5)j]\cdot (9.3i + 9.5j) = (17.9i + 14.6j)\cdot (9.3i + 9.5j) = 305.17

d) The component of a along the direction of b is:

a*cos(\theta) = \frac{a\cdot b}{|b|} = \frac{128.43}{\sqrt{9.3^{2} + 9.5^{2}}} = 9.66

I hope it helps you!                        

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