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ozzi
3 years ago
15

A beam of light shining from water to air strikes the surface at an angle greater than 48° and produces total internal reflectio

n. If the incident beam is at a 50° angle, at what angle is the reflected beam?
Physics
1 answer:
shepuryov [24]3 years ago
3 0
<span>To find the solution for this problem, let us remember that the angle of incidence and the angle of reflection are always the same. Thus,  the reflected beam would be at an angle of 50 degrees as wel</span>l.

<span> Total internal reflection means that the total amount of incident light at the boundary between two media gets reflected, and therefore no beam of light is transmitted to </span>the air in this case.

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Answer:

A title

Explanation:

Because this is middle school.

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3 years ago
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A 500kg car is driving through a neighborhood at 20m/s. Then the car hits a speed bump which causes it to slow to 15m/s. What wa
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Based on the formula for calculating impulse, the impulse of the speed bump to the car is 2500 Ns.

<h3>What is the impulse of the speed bump?</h3>

  • Impulse = change in momentum
  • momentum = mass * velocity

Change in momentum = mu - mv

where u is initial velocity

v is final velocity

Impulse = 500 * 20  - 500 * 15

Impulse = 2500 Ns

Therefore, the impulse of the speed bump to the car is 2500 Ns.

Learn more about impulse at: brainly.com/question/297527

5 0
3 years ago
What is the freezing point of an aqueous solution that boils at 101 degrees C? Kfp = 1.86 K/m and Kbp = 0.512 K/m. Enter your an
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Answer:

-3.63 degree Celsius

Explanation:

We are given that

Boiling point of solution=T_b=101^{\circ} C

Boiling point water=100 degree Celsius

K_f=1.86K/m

K_b=0.512 K/m

\Delta T_b=T-T_0

Where T=Boiling point of solution

T_0=Boiling point of pure solvent

\Delta T_b=101-100=1^{\circ}C

\Delta T_b=k_bm

Using the formula

1=0.512\times m

Molality,m=\frac{1}{0.512} m

\Delta T_f=k_fm

Using the formula

\Delta T_f=\frac{1}{0.512}\times 1.86

\Delta T_f=3.63 C

We know that

\Delta T_f=T_0-T_1

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T_1= Freezing point of solution

Using the formula

3.63=0-T_1

Freezing point of water=0 degree Celsius

T_1=0-3.63=-3.63 C

Hence, the freezing point of solution=-3.63 degree Celsius

7 0
3 years ago
Which of these best describes how the kinetic energy of carbon dioxide molecules change as the carbon dioxide is heated?
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B.
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4 0
3 years ago
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An object has 90,000 J of kinetic energy and is moving at 12 m/s. What is the objects mass?
trapecia [35]

Answer:

plug it into your calculator

Explanation:

Kinetic energy = KE = Joules = J

KE= 1/2mv^2

90,000 = 1/2 m (12^2)

180,000 = m (144)

m = 180,000 / 144

4 0
3 years ago
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