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miv72 [106K]
2 years ago
10

Because of the differences in physical properties, the lithosphere is effectively detached from the asthenosphere.

Physics
1 answer:
aivan3 [116]2 years ago
8 0

Because of the differences in physical properties, the lithosphere is effectively detached from the asthenosphere, allowing layers to move separately.

<h3>What is  Lithosphere?</h3>
  • The Lithosphere, the earth's powerful outer layer, lies over the weak Asthenosphere.
  • Under the lithosphere is the Asthenosphere, a hotter and weaker portion of the mantle.
  • The lithosphere is divided into roughly twenty-four smaller pieces, or lithospheric plates.
  • These plates are always moving.
<h3>What is the theory of plate tectonics?</h3>

According to the widely recognised scientific hypothesis known as plate tectonics, the Earth's lithosphere is made up of many sizable tectonic plates that have been steadily moving for nearly 3.4 billion years.

Learn more about Lithosphere here:

brainly.com/question/13334695

#SPJ4

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You drop a rock from rest from the top of a tall building.1)how far has the rock fallen in 2.60 s?
Bess [88]
Answer:
distance = 33.124 meters

Explanation:
To solve this question, we will use one of the equations of motion which is:
s = ut + 0.5a * t^2
where:
s is the distance that we want to get
u is the initial velocity = 0
a is the acceleration due to gravity = 9.8 m/sec^2
t is the time = 2.6 sec

Substitute with the givens in the equation to get the distance as follows:
s = ut + 0.5a * t^2
s = (0)(2.6) + 0.5(9.8)(2.6)^2
s = 33.124 meters

Hope this helps :)
7 0
3 years ago
A 9.0-V battery moves 20 mC of charge through a circuit running from its positive terminal to its negative terminal. How much en
dem82 [27]

Answer:

E = 0.18 J

Explanation:

given,

Potential of the battery,V = 9 V

Charge on the circuit, Q = 20 m C

                                        = 20 x 10⁻³ C

energy delivered in the circuit

E = Q V

E = 20 x 10⁻³ x 9

E =  180 x 10⁻³

E = 0.18 J

Energy delivered in the circuit is equal to E = 0.18 J

7 0
3 years ago
An irregular object of mass 3 kg rotates about an axis, about which it has a radius of gyration of 0.2 m, with an angular accele
Citrus2011 [14]

Answer:

The magnitude of the applied torque is 6.0\times10^{-2}\ N-m

(e) is correct option.

Explanation:

Given that,

Mass of object = 3 kg

Radius of gyration = 0.2 m

Angular acceleration = 0.5 rad/s²

We need to calculate the applied torque

Using formula of torque

\tau=I\times\alpha

Here, I = mk²

\tau=mk^2\times\alpha

Put the value into the formula

\tau=3\times(0.2)^2\times0.5

\tau=0.06\ N-m

\tau=6.0\times10^{-2}\ N-m

Hence, The magnitude of the applied torque is 6.0\times10^{-2}\ N-m

7 0
3 years ago
For work to be done on an object,
djverab [1.8K]

Answer:B

Explanation:

For work to be done, the object must move some distance as a result of a force

3 0
3 years ago
You and a friend work in buildings five equal-length blocks apart, and you plan to meet for lunch. Your friend strolls leisurely
Pavel [41]

Answer:

Your friend is 2.143 blocks from the restaurant.

You are 2.857 blocks from the restaurant.

Explanation:

Let t be the time both you and your friend take to walk to the restaurant.

The distance (m) from your building to the restaurant is your walking time t times your speed v1

s_1 = v_1t = 1.6t

Similarly the distance (m) from your friend building to the restaurant:

s_2 = v_2t = 1.2t

Let b be the length (in m) of a block, the total distance of 5 blocks is 5b

s_1 + s_2 = 5b

1.6t + 1.2t = 5b

2.8t = 5b

t = 5b/2.8 = 25b/14

s_2 = 1.2t = 1.2(25b/14) = 2.143b

So your friend are 2.143b meters from the restaurant, since each block is b meters long, 2.143b meters would equals to 2.143b/b = 2.143 blocks. And you are 5 - 2.143 = 2.857 blocks from the restaurant.

7 0
3 years ago
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