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2 years ago

Because of the differences in physical properties, the lithosphere is effectively detached from the asthenosphere.

1 answer:

8 0

Because of the differences in physical properties, the lithosphere is effectively detached from the asthenosphere, allowing layers to move separately.

<h3>What is Lithosphere?</h3>

The Lithosphere, the earth's powerful outer layer, lies over the weak Asthenosphere.
Under the lithosphere is the Asthenosphere, a hotter and weaker portion of the mantle.

The lithosphere is divided into roughly twenty-four smaller pieces, or lithospheric plates.
These plates are always moving.

<h3>What is the theory of plate tectonics?</h3>

According to the widely recognised scientific hypothesis known as plate tectonics, the Earth's lithosphere is made up of many sizable tectonic plates that have been steadily moving for nearly 3.4 billion years.

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Billiard ball A strikes another ball B of the same mass, which is at rest, such that after the impact they move at angles ΘA and

Drupady [299]

Answer:

7.6427m/s

Explanation:

Given: $v_a=4.7m/s, \theta_a=33.0\textdegree and \ v_b=4.5m/s$

#Applying the conservation of momentum along the x-axis: $mv_i=mv_acos\theta_a+mv_bcos\theta_b$

#And along y-axis:

$0=-sin\theta_a+mv_bsin\theta_b$

#Solving for $\theta_b$ :

$sin\rheta_b=\frac{v_a}{v_b}sin\theta_a=4.7/4.5\times sin33.0\textdegree\\=0.5688\\\therefore \theta_b=34.67\textdegree$

#By substitution in the x-axis equation:

$v_i=4.7cos 33.0\textdegree +4.5cos 34.67\textdegree\\=7.6427m/s$

Hence the original speed of the ball before impact is 7.6427m/s

4 0

3 years ago

A researcher reports an f-ratio with df = 3, 36 for an independent-measures experiment. how many treatment conditions were compa

user100 [1]

The correct option is B.

There were 4 treatment conditions compared in the experiment.

F ratio plays an essential role in performing a particular dataset of ANOVA. F ratio is particularly a ratio which is obtained by the between-group variance or it is also called MSB and also within-group variance known as MSW. Any F-ratio which is computed is compared with the critical F-ratios from the table as it will check out if there are any variations available between the groups or not.

The researcher reports an F-ratio where the degrees of freedom = 3, 36.

F-ratio is obtained by the calculation of dividing the Mean squared errors because of the treatment by the Mean squared error which occurs due to error.

For the particular case, the researcher reports an F-ratio having degrees of freedom = 3, 36. It is indicating that the treatments are being distributed with degrees of freedom which is 3 and specified errors are distributed with degrees of freedom which is 36.

Let the treatments which were involved in the study can be denoted by k.

Let the total number of individuals involved in the study can be taken as N.

Then, the treatments will be having degrees of freedom as,

$df_{treatments}$ = k-1

3=k-1

k=3+1=4

Therefore, the required treatment condition number that was compared is 4.

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6 0

1 year ago

Please help ASAP.

Elden [556K]

Answer:

1st question c part

2nd question c part

8 0

3 years ago

A lightbulb has a resistance of 195 Ω and carries a current of 0.62 A.

ki77a [65]

Answer:

Explanation:

Power is current times voltage:

P = IV

Voltage is current times resistance:

V = IR

Therefore:

P = I²R

Given I = 0.62 A and R = 195 Ω:

P = (0.62 A)² (195 Ω)

P ≈ 75 W

8 0

3 years ago

Determine the frequency of the 2nd harmonic of a spring that has a 3rd harmonic resonance of f3=512 Hz.

Elena L [17]

Answer:

1) 341 Hz

Explanation:

When a string vibrates, it can vibrate with different frequencies, corresponding to different modes of oscillations.

The fundamental frequency is the lowest possible frequency at which the string can vibrate: this occurs when the string oscillate in one segment only.

If the string oscillates in n segments, we say that it is the n-th mode of vibration, or n-th harmonic.

The frequency of the n-th harmonic is given by

$f_n = nf_1$