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3 years ago

13

A bag of sweets contains only two different flavours - strawberry and orange The probability that a sweet is strawberry flavour

is 0.8 What is the probability that a sweet is orange flavour?

2 answers:

sashaice [31]3 years ago

7 0

Answer:

out of 1 would be 0.2

Step-by-step explanation:

alex41 [277]3 years ago

3 0

Answer:

Step-by-step explanation:

Hello

The answer is 0.2

1 - 0.8 = 0.2

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Calculate the limit values:

Nataliya [291]

A) This particular limit is of the indeterminate form,
$\frac{ \infty }{ \infty }$
if we plug in infinity directly, though it is not a number just to check.

If a limit is in this form, we apply L'Hopital's Rule.

's
$Lim_{x \rightarrow \infty } \frac{ ln(x ^{2} + 1 ) }{x} = Lim_ {x \rightarrow \infty } \frac{( ln(x ^{2} + 1 ) ) '}{x ' }$
So we take the derivatives and obtain,

$Lim_ {x \rightarrow \infty } \frac{ ln(x ^{2} + 1 ) }{x} = Lim_{x \rightarrow \infty } \frac{ \frac{2x}{x^{2} + 1} }{1}$

Still it is of the same indeterminate form, so we apply the rule again,

$Lim_{x \rightarrow \infty } \frac{ ln(x ^{2} + 1 ) }{x} = Lim_{x \rightarrow \infty } \frac{ 2 }{2x}$

This simplifies to,

$Lim_{x \rightarrow \infty } \frac{ ln(x ^{2} + 1 ) }{x} = Lim_{x \rightarrow \infty } \frac{ 1 }{x} = 0$

b) This limit is also of the indeterminate form,

$\frac{0}{0}$
we still apply the L'Hopital's Rule,

$Lim_ {x \rightarrow0 }\frac{ tanx}{x} = Lim_ {x \rightarrow0 } \frac{ (tanx)'}{x ' }$

$Lim_ {x \rightarrow0 }\frac{ tanx}{x} = Lim_ {x \rightarrow0 } \frac{ \sec ^{2} (x) }{1 }$

When we plug in zero now we obtain,

$Lim_ {x \rightarrow0 }\frac{ tanx}{x} = Lim_ {x \rightarrow0 } \frac{ \sec ^{2} (0) }{1 } = \frac{1}{1} = 1$
c) This also in the same indeterminate form

$Lim_ {x \rightarrow0 }\frac{ {e}^{2x} - 1 - 2x}{ {x}^{2} } = Lim_ {x \rightarrow0 } \frac{ ({e}^{2x} - 1 - 2x)'}{( {x}^{2} ) ' }$

$Lim_ {x \rightarrow0 }\frac{ {e}^{2x} - 1 - 2x}{ {x}^{2} } = Lim_ {x \rightarrow0 } \frac{ (2{e}^{2x} - 2)}{ 2x }$

It is still of that indeterminate form so we apply the rule again, to obtain;

$Lim_ {x \rightarrow0 }\frac{ {e}^{2x} - 1 - 2x}{ {x}^{2} } = Lim_ {x \rightarrow0 } \frac{ (4{e}^{2x} )}{ 2 }$

Now we have remove the discontinuity, we can evaluate the limit now, plugging in zero to obtain;

$Lim_ {x \rightarrow0 }\frac{ {e}^{2x} - 1 - 2x}{ {x}^{2} } = \frac{ (4{e}^{2(0)} )}{ 2 }$

This gives us;

$Lim_ {x \rightarrow0 }\frac{ {e}^{2x} - 1 - 2x}{ {x}^{2} } =\frac{ (4(1) )}{ 2 }=2$

d) $Lim_ {x \rightarrow +\infty }\sqrt{x^2+2x}-x$

For this kind of question we need to rationalize the radical function, to obtain;

$Lim_ {x \rightarrow +\infty }\frac{2x}{\sqrt{x^2+2x}+x}$

We now divide both the numerator and denominator by x, to obtain,

$Lim_ {x \rightarrow +\infty }\frac{2}{\sqrt{1+\frac{2}{x}}+1}$

This simplifies to,

$=\frac{2}{\sqrt{1+0}+1}=1$

5 0

3 years ago

Which inequality is graphed on the number line shown?

bearhunter [10]

The graph is to the left of -3, so it's < or ≤.
The circle is filled in so -3 also satisfies the inequality, so it's ≤.
The answer is B. x≤-3.

4 0

3 years ago

A tape diagram. 0 dollars is 0 percent. Question mark dollars is 35 percent. 49 dollars is 100 percent.

Leno4ka [110]

$31.85
$49 multiply by .35 = 17.15
$49-17.15 = $31.85

8 0

2 years ago

Read 2 more answers

In ANOVA analyses, when the null hypothesis is rejected, we can test for differences between treatment means by ________. Group

nikklg [1K]

Answer:

When conducting an analysis of variance analysis on a set of samples and the null hypothesis is rejected, we can test for the difference between treatment can be tested with the aid of a t-test. This is employed when 2 related groups are involved. Independent sample, paired sample or one-sample t-test can be conducted.

Step-by-step explanation:

A t-test is a test statistic used to make inferences that determine the differences that exist statistically between 2 related groups. It tells us if the 2 groups tested are from the same population. There are 3 types of t-test namely independent sample t-test, paired-sample t-test and one-sample t-test

5 0

3 years ago

A taxi charges $20 flat fee for the first 5 miles (even if it takes the rider one mile the cost is $20) and after that the addit

Free_Kalibri [48]

Ok so, we have the fact that 1.20 per mile Lets represent m as each additional mile so we have 1.20m which is That much per additional mile So For the first 5 functions we have f(1) = 20 f(2) = 20 f(3) = 20 f(4) = 20 f(5) = 20 Only for the first 5 miles though, since it is a flat fee. So for the additional miles we go back to what I said in the first Paragraph. 1.20m That is for additional miles, so that will be added to 20 So if you travel more than 5 miles the function looks like this: f(x) = 20 + 1.20m So the first 5 miles it is: f(x) = 20 For 7 mles the function would look like: f(7) = 20 + 1.20(2) It is a 2 because it is the additional mile, which is 2 hope this helps

7 0

3 years ago