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natali 33 [55]
3 years ago
7

Does anyone know 3²?

Mathematics
1 answer:
Vadim26 [7]3 years ago
8 0

Answer:

It is 9.

Step-by-step explanation:

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PLS HELP WILL MARK BRAINLIEST Which graph represents the function f(x)=2⋅4x ? (ANSWERS ARE IN PICTURES)
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It's going to be the top right picture
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3 years ago
WILL GIVE BRAINLIEST!<br> What’s the perimeter and area of this figure?
yulyashka [42]

Perimeter is 7y+2

Area is 4y^2+1y

3 0
3 years ago
Whats the y intercept of y=4x -3
AleksAgata [21]

Answer:

-3

Step-by-step explanation:

the y intercept is the number that does not have a variable behind it (3)

the slope is the number that does have a variable behind it (4)

6 0
2 years ago
Read 2 more answers
A rocket is launched straight up from the ground with an initial velocity of 192 feet per second. The equation for the height of
Ivenika [448]

The equation for the height of the rocket at time t given

h= -16t^2+192t

We have to find the time t, when the rocket reaches 560 feet.

That means we have to find t when h = 560 ft. we will place 560 in the place of h to find t now.

h= -16t^2+192t

560 = -16t^2+192t

In the right side, we can check -16 is the common factor. So we will take out -16 from the rigbht side.

560 = -16(t^2 - 12t)

To get rid of -16 from the right side and move it to left side, we will divide both sides by -16.

560/-16 = -16(t^2-12t)/-16

-35 = t^2 -12t

Now we will move -35 to the righ side by adding 35 to both sides.

-35+35 = t^2-12t+35

0 = t^2 -12t+35

t^2-12t+35 = 0

We will factorize thee left side to find the values of t now. We need to find a pair of factors of 35 that by adding them we will get -12.

The pair of factors of 35 are -5 and -7 and by adding -5-7 we will get -12.

t^2-12t+35 =0

(t-5)(t-7) =0

So by using zero product property we will get

t-5 =0

t-5+5 = 0+5

t=5

Also t-7 =0

t-7+7 = 0+7

t=7

So we have got the rocket reaches at 560ft when t = 5 seconds and also when t = 7 seconds.

Now part b.

When the rocket completes its trajectory and hits the ground then the height or h = 0. So we will place h = 0 there in the equation.

h= -16t^2+192t

0= -16t^2 + 192 t

0 = -16(t^2-12t)

-16(t^2-12t) = 0

We will move -16 to the other side by dividing it to both sides.

-16(t^2-12t)/-16 = 0/-16

t^2-12t = 0

We will take out the common factor t from the left side. By taking out t we will get,

t(t-12) = 0

We will use zero product property now. By using that we will get,

t = 0

ans also t-12 = 0

t-12+12 = 0+12

t = 12

When the rocket completes its trajectory and hits the ground the time t can not be 0. When t =0, the rocket starts the trajectory.

So when the rocket completes its trajectory and hits the ground ,

then t = 12seconds.

So we have got the required answers.

6 0
3 years ago
Help please :/<br> jejsjsj
Alla [95]

Answer:

-6

-21

12

Step-by-step explanation:

can i get brainly

6 0
2 years ago
Read 2 more answers
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