11 family members are going on a trip together. They have cars that only fit 4 people how many cars will they need to take?

Mathematics

1 answer:

Shalnov [3]2 years ago

6 0

They will need 3 cars, but one of the cars will be having 3 passengers instead of 4. :)

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Jane, Jasmine, and Jocelyn have record collections. Jane has 3 times as many records as Jocelyn has. Jasmine has 2 more than twi

dangina [55]

X = jane, y = jasmine, z = jocelyn

x + y + z = 56
x = 3z
y = 2z + 2

3z + 2z + 2 + z = 56
6z + 2 = 56
6z = 56 - 2
6z = 54
z = 54/6
z = 9 <==== jocelyn

x = 3z
x = 3(9)
x = 27 <=== jane

y = 2z + 2
y = 2(9) + 2
y = 18 + 2
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2 years ago

Pls helpppp meeeeee :(

Alja [10]

Answer:

Sam

Step-by-step explanation:

Sam made a mistake when he said $10^2 -20$ . The steps should have been:

$2n^2-20=2(5)^2-20\\2(25)-20\\50-20=30$

You are supposed to square 5 first before multiplying 2. Sam multiplied by 2 first. The correct answer is 30.

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2 years ago

Will give brainliest + 5 star rating!

koban [17]

Answer is choice C) 4x^2-3x+9

You list off the terms in a way where the largest exponent term comes first, then the second largest exponent is next, and so forth. Note how the last term 9 is the same as 9x^0. The term 3x is equivalent to 3x^1. So what we really have is 4x^2-3x^1+9x^0. The exponents count down: 2, 1, 0

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3 years ago

Read 2 more answers

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ra1l [238]

Answer:

what class are you in? if you have a book you can use this site called slader it gives you every answer for free and there is steps. HOPE THIS HELPS.

Step-by-step explanation:

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