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2 years ago

11 family members are going on a trip together. They have cars that only fit 4 people how many cars will they need to take?

Mathematics

1 answer:

Shalnov [3]2 years ago

6 0

They will need 3 cars, but one of the cars will be having 3 passengers instead of 4. :)

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An advertising company charges $60 per half-page advertisement and $100 per full-page advertisement. Michael has a budget of $13

krek1111 [17]

Answer:

The number of half-page advertisements is 4.

The number of Full-page advertisements is 11.

Step-by-step explanation:

According to the Question,

Given, An advertising company charges $60 per half-page advertisement and $100 per full-page advertisement. Michael has a budget of $1340 to purchase 15 advertisements.

Let, 'x' be the number of half-page advertisements and 'y' be the number of full-page advertisements.

Thus, 60x + 100y is the money charged, and given that he has a budget of $ 1340.

60x + 100y = 1340

And, the number of advertisements is 15. So, the other equation is

x + y = 15

Now, We have Two Equations,

60x + 100y = 1340 and x + y = 15

the solution of the system is Put x=(15-y) in Equation 60x + 100y = 1340

60 (15-y) + 100y = 1340

900 - 60y + 100y = 1340

40y = 1340 - 900

40y = 440

y = 440/40

y = 11 So, For x = 15 - y ⇒ 15-11 ⇒ x=4 .

Thus, the number of half-page advertisements is 4 and The number of Full-page advertisements is 11 .

6 0

2 years ago

The drama club is selling tickets to its play. An adult ticket costs $15 and a student ticket costs $11. The auditorium will sea

spin [16.1K]

Answer:

83 adult tickets and 217 student tickets.

Step-by-step explanation:

Let number of adult tickets sold = $x$

Given that total number of tickets = 300

So, number of student tickets = 300 - $x$

Cost of adult ticket = $15

Cost of student ticket = $11

Total collection from adult tickets = $ $15x$

Total collection from student tickets = $(300-x)\times 11 = 3300-11x$

Given that overall collection = $3630

$15x+(3300-11x) = 3630\\\Rightarrow 15x-11x=3630-3300\\\Rightarrow 4x = 330\\\Rightarrow x = 82.5$

So, for atleast $3630 collection, there should be 83 adult tickets and (300-83 = 217 student tickets.

Now , collection = $3632

4 0

2 years ago

PLEASE HELP MEEEEEEEE IM BEGGING

suter [353]

PLEASE HELP MEEEEEEEE IM BEGGING

4 0

2 years ago

Read 2 more answers

Which step was the first error made? -3\left(2x-3\right)=33−3(2x−3)=33 -6x+6=33−6x+6=33 step 1 -6x=27−6x=27 step 2 \frac{\left(-

Afina-wow [57]

Given:

The equation is

$-3(2x-3)=33$

The incorrect solution steps are given.

To find:

The first error.

Solution:

We have,

$-3(2x-3)=33$

Using distributive property, we get

$-3(2x)-3(-3)=33$

$-6x+9=33$

The given step 1 is $-6x+6=33$ , which is not correct.

Therefore, there is first error in step 1 because the distribution property is not used properly.

Hence, the correct option is D.

6 0

2 years ago

mike can buy red push pins in packages of 24 and yellow push pins in packages of 36. what is the least number of each color he m

Masja [62]

The least he can buy is 3 of the red and 2 of the yellow which equals 5 packes

5 0

2 years ago

11 family members are going on a trip together. They have cars that only fit 4 people how many cars will they need to take?￼

11 family members are going on a trip together. They have cars that only fit 4 people how many cars will they need to take?