Answer:
12 L of 40% sulfuric acid solution and 8 L of 10% sulfuric acid solution are needed to make 20 L of sulfuric acid solution.
Explanation:
For first solution of sulfuric acid :
C₁ = 40% , V₁ = ?
For second solution of sulfuric acid :
C₂ = 10% , V₂ = ?
For the resultant solution of sulfuric acid:
C₃ = 28% , V₃ = 20L
Also,
<u>V₁ + V₂ = V₃ = 20L</u> ......................................(1)
Using
<u>C₁V₁ + C₂V₂ = C₃V₃</u>
<u>40×V₁ + 10×V₂ = 28×20</u>
So,
40V₁ + 10V₂ = 560........................................(2)
Solving 1 and 2 as:
V₂ = 20 - V₁
Applying in 2
40V₁ + 10(20 - V₁) = 560
40V₁ + 200 - 10V₁ = 560
30V₁ = 360
<u>V₁ = 12 L</u>
So,
<u>V₂ = 20 - V₁ = 8L</u>
<u><em>12 L of 40% sulfuric acid solution and 8 L of 10% sulfuric acid solution are needed to make 20 L of sulfuric acid solution.</em></u>
It bonds atoms together to create molecules
Answer: 3.01 x 10^24 atoms
Explanation:
Based on Avogadro's law:
1 mole of any substance has 6.02 x 10^23 atoms
So, 1 mole of SI = 6.02 x 10^23 atoms
5.0 moles = Z atoms
To get the value of Z, cross multiply:
(Z atoms x 1 mole) = (6.02 x 10^23 atoms x 5.0 moles)
Z atoms•1 mole = 30.1 x 10^23 atoms•moles
Divide both sides by 1 mole
Z atoms•1 mole / 1 mole = 30.1 x 10^23 atoms•moles / 1 mole
Z = 30.1 x 10^23 atoms
[Place Z in standard form
So, Z = 3.01 x 10^24 atoms]
Thus, there are 3.01 x 10^24 atoms in 5.0 moles in SI
H2O is the Bronsted-Lowry acid in the forward reaction, donating an H+ to CH3, and CH4 is the Bronsted-Lowry acid in the reverse direction, donating an H+ to OH-.
Solution:- Halogens are fluorine, chlorine, bromine, iodine and Astatine(F, Cl, Br, I and At) and these are present in the 7A group of the periodic table. In modern periodic table this group is written as 17th group. This group elements have 7 valence electrons and so they are in group 7A.
So, the right choice is D. 7A.
