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4 years ago

13

Which statement is not true regarding nuclear reactions? Alpha, beta, and gamma are types of radiation. Nuclear reactions involv

e breaking and forming covalent bonds. Nuclear reactions involve a change in an atom's nucleus. Radioactive elements have unstable nuclei.

1 answer:

svet-max [94.6K]4 years ago

7 0

Alpha I believe not sure

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The frequency of light that has a wavelength of 310 mm

Vilka [71]

Black light hope this helps

4 0

3 years ago

Given the incomplete equation representing a reaction:

sergey [27]

Answer : The formula of the missing product is, $OH^_$

Explanation :

The given incomplete equation representing a reaction,

$2Na(s)+2H_2O(l)\rightarrow 2Na^+(aq)+2__(aq)+H_2(g)$

When the sodium metal react with the water then it gives a colorless solution of sodium hydroxide and hydrogen gas. In the solution, sodium hydroxide is present in the form of ions i.e, $Na^+$ and $OH^-$ ions.

The balanced chemical reaction will be,

$2Na(s)+2H_2O(l)\rightarrow 2Na^+(aq)+2OH^-(aq)+H_2(g)$

Therefore, the formula of the missing product is, $OH^_$

3 0

3 years ago

Read 2 more answers

Energy flows from the plankton to a number of other organisms when the plankton are eaten. Describe how the decrease in plankton

PIT_PIT [208]

Less plankton would mean that all the organisms that eat plankton would start to die off because they have no source of energy.

7 0

3 years ago

If 2.29 kg of hydrazine are used in a rocket engine and 3.14 kg of oxygen are available for reaction,

Valentin [98]

Answer:

Explanation:

Reaction of hydrazine is

N2H4 + O2 --> N2 + 2H2O

Mass of hydrazine mole = 14x2 + 1x4 = 32g/Mol

Mass of O2 mole = 16x2 = 32g/Mol

Number of moles in 2.29kg of hydrazine

2290/32=71.56Moles

1mol of hydrazine required to react with 1mol of O2

Amount of O2 required to react with hydrazine

71.56*32=2290

Required O2 amount is exactly the same.

Therefore limiting reactant is hydrazine and excess of 850g of O2 will be in excess.

7 0

4 years ago

Can somebody help me. Will mark brainliest.

pickupchik [31]

Answer:

2.27%

Explanation:

The observed value of the boiling point = 71.8°C

The actual value of the boiling point = 70.2°C

We need to find the percentage error of the student's measurement. The percentage error in any value is given by :

$\%=\dfrac{\text{calculated value-actual value}}{\text{actual value}}\times 100\\\\=\dfrac{71.8-70.2}{70.2}\times 100\\\\=2.27\%$

So, the required percentage error is 2.27%.

8 0

3 years ago